Formal Proof of ANOVA's F Distribution?

AI Thread Summary
The discussion centers on the formal proof that the ratio of mean squares in ANOVA, specifically MS between to MS within, follows an F distribution under the null hypothesis. It highlights that the ratio arises from two independent chi-square random variables, as each mean square term can be represented as a quadratic form. The conditions of normality and the independence of the quadratic forms under the null hypothesis support this conclusion. The explanation references Wikipedia's assertion regarding the relationship between chi-square and F distributions. Overall, the mathematical foundation for the F distribution in ANOVA is rooted in the properties of chi-square distributions and their degrees of freedom.
Boot20
Messages
8
Reaction score
0
Hello all,

Does anyone know where I could find a formal proof that

\frac{\text{MS between}}{\text{MS within}}

has a F distribution under the null in ANOVA?
 
Physics news on Phys.org
Wikipedia states that the ratio of two chi-square random variables is F. If each MS term is normal then their sum will be Chi-squared.
 
In ANOVA each sum of squares can be pictured as a quadratic form, and under the null hypothesis the quadratic forms are either exactly chi-squared (if normality is assumed) or approximately chi-squared (under some general regularity conditions). The model assumptions and the null hypothesis ensure that the different quadratic forms are independent, so

(MS between)/(MS within)

is a ratio of independent chi-squares over their degrees of freedom which, by definition, gives an F distribution.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...
Back
Top