Answer: Torque of Swallow on 40 N Rod with 1 m Length

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SUMMARY

The discussion centers on calculating the force exerted by a string to maintain a horizontal position of a 40 N rod when a 2.00 kg swallow lands on it. The rod is 1 m long, with the swallow landing 30 cm from the hinge. The initial force exerted by the string is determined to be 20 N, but further clarification on the moment arm and force balance is required to finalize the solution. The key equations involve summing forces and moments about the hinge point.

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Homework Statement



James Gomer holding a uniform 40 N rod of length 1 m horizontally with a hinge on its left end and a vertical string on the right end. Now suppose a fully laden swallow with a mass of 2.00 kg lands and squawks loudly on the rod at a point 30.0 cm to the right of the hinge. Now what is the force exerted by the string to keep the rod horizontal?

Homework Equations





The Attempt at a Solution



I figured out that the string with no force exerted on the rod is 20N, so Far I have

Ʃfnet = 2kg*9.8*20(moment arm) - F*20

I don't think I have my setup correct though.. I'm just not visualizing this well
 
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What point are you taking moments about? List the forces and their orthogonal distances from that point.
 

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