Answering JK Flip Flop Questions: How do I get xA' + x'A + xB?

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SUMMARY

The discussion focuses on deriving the output equation for a JK flip flop circuit with inputs J = x and K = xB'. The key equation used is Q+ = JQ' + K'Q, leading to the final result of xA' + x'A + xB. The complement of K, denoted as K', is essential for this derivation. Understanding excitation tables is also crucial for comprehending the behavior of JK flip flops in this context.

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Electronics students, digital circuit designers, and anyone involved in understanding or designing JK flip flop circuits will benefit from this discussion.

seang
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We're analyzing JK flip flop circuits and I don't understand it.

So, Given that J = x, and K = xB' , my notes say that Q+ = JQ' + K'Q. I understand that. Then, substituting, we get xA' + x'A + xB.

I have no idea how that final result was obtained. Can anyone help me with this?
 
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Show and think about the circuit.
 
K = x'B

then what's the complement of K?

K' = ?

And look up the excitation tables.
 
Last edited:

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