Sequential Logic & JK Flip Flops

  • Thread starter Thread starter rofln
  • Start date Start date
  • Tags Tags
    Logic
Click For Summary
SUMMARY

The discussion centers on the completion of a truth table for JK Flip Flops, specifically addressing the confusion surrounding the output of an AND gate connected to the JK Flip Flop. The participant correctly identifies the characteristic tables for JK and D Flip Flops but struggles with the expected outputs in certain rows of the truth table. The participant's calculations yield zeros for A(t+1) and B(t+1) in rows 2 and 4, conflicting with the solutions manual, which indicates ones in those rows. Clarification on the behavior of the JK Flip Flop in response to input conditions is necessary for accurate completion of the truth table.

PREREQUISITES
  • Understanding of JK Flip Flop characteristic tables
  • Knowledge of D Flip Flop characteristic tables
  • Familiarity with truth tables for logic circuits
  • Basic concepts of AND gate logic
NEXT STEPS
  • Review the operation of JK Flip Flops and their input-output behavior
  • Study the differences between JK and D Flip Flops
  • Practice creating truth tables for various logic circuits
  • Explore timing diagrams for JK Flip Flops to understand state transitions
USEFUL FOR

Students studying digital logic design, electronics enthusiasts, and anyone preparing for exams involving sequential logic circuits and flip flop behavior.

rofln
Messages
6
Reaction score
0

Homework Statement


Complete the truth table for the following
http://forum.allaboutcircuits.com/image_cache/httpwww.freeimagehosting.netuploadsd537e2dd9a.jpg


Homework Equations


JK Flip Flop Characteristic Table
D Flip Flop Characteristic Table


The Attempt at a Solution


I understand how to make truth tables for logic circuits and I know the characteristic tables. But what is really stumping me is the AND gate that go to the JK Flip flop. It seems to me that whenever x and A are put together in the AND gate, it will always be zero except for the two entries where A and X are equal to one. I have the solutions manual and my answer is incorrect. It has 1's in row 2 and 4 but I have absolutely no idea how.
Here is what I have down just for the A column.
A B X A(t+1) B(t+1)
0 0 0 0
0 0 1 0
0 1 0 0
0 1 1 0
1 0 0 0
1 0 1 1
1 1 0 0
1 1 1 1

Any help and/or explanation would be very much appreciated, my final is on Wednesday and I want to get this topic rock solid in my head.
 
Last edited by a moderator:
Physics news on Phys.org
If the circuit powers up with A=0, B=0 as far as I can see it's game over and nothing ever changes no matter what you do to X. JK is allways 00 = "no change" so A(t+1) = 0. D is allways 0 so B(t+1)=0.

So I can't see how they get a different answer to you for row two.
 
I make A(t+1) and B(t+1) both = 0 for rows 2 and 4.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
20
Views
4K
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 6 ·
Replies
6
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K