Antiderivative of a function problem

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Homework Help Overview

The discussion revolves around finding the derivative of a function defined as an integral, specifically \( g(x) = \int_{2}^{\sin x} \sqrt{1 - t^2} dt \). Participants are exploring the application of the Fundamental Theorem of Calculus in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss how to find \( g'(x) \) using the Fundamental Theorem of Calculus and the chain rule. There are attempts to clarify the necessity of finding the antiderivative of \( \sqrt{1 - t^2} \) and suggestions to use substitutions like \( t = \sin(u) \) or \( t = \cos(u) \). Some participants question the relevance of finding the antiderivative in this specific problem.

Discussion Status

The discussion is active, with various participants providing insights into the application of calculus principles. Some guidance has been offered regarding the use of the Fundamental Theorem of Calculus and the chain rule, while others are exploring different interpretations of the problem.

Contextual Notes

There is a mention of a related problem involving a definite integral, which raises questions about the nature of derivatives of constants and the implications of variable limits of integration.

Slimsta
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Homework Statement


[tex]$g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt$[/tex]
whats g'(x)...

Homework Equations


The Attempt at a Solution


how to find the antiderivative of sqrt(1-t^2)?
 
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Try t=sin(u) or t=cos(u)
 
I have edited your formula slightly so that it now shows g(x), not just (x). You had extra $ characters that shouldn't have been there.
Slimsta said:

Homework Statement


[tex]g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt[/tex]
whats g'(x)...


Homework Equations





The Attempt at a Solution


how to find the antiderivative of sqrt(1-t^2)?
Use the Fundamental Theorem of Calculus to find g'(x). You will also need the chain rule since your integral isn't strictly a function of just x, but is a function of sin(x).
 
Hi Slimsta! :smile:
Slimsta said:
how to find the antiderivative of sqrt(1-t^2)?
Mark44 said:
Use the Fundamental Theorem of Calculus to find g'(x) …

Just to add to what Mark44 :smile: says …

the beauty of using the Fundamental Theorem of Calculus is that you don't need to know the antiderivative. :wink:
 
Slimsta said:

Homework Statement


[tex]g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt[/tex]
whats g'(x)...


Homework Equations





The Attempt at a Solution


how to find the antiderivative of sqrt(1-t^2)?

rock.freak667 said:
Try t=sin(u) or t=cos(u)
The problem does not ask you to find the anti-derivative nor is it necessary.
Letting y= sin(x), this is
[tex]g(y)=\int_2^y \sqrt{1- t^2} dt[/itex]<br /> You can find dg/dy directly from the "Fundamental Theorem of Calculus" and then use the chain rule to find dg/dx.[/tex]
 
HallsofIvy said:
The problem does not ask you to find the anti-derivative nor is it necessary.
Letting y= sin(x), this is
[tex]g(y)=\int_2^y \sqrt{1- t^2} dt[/itex]<br /> You can find dg/dy directly from the "Fundamental Theorem of Calculus" and then use the chain rule to find dg/dx.[/tex]
[tex] <br /> okay, that make sense but what if i have a function like this:<br /> [tex]$\int _{3\pi /4}^{\pi }(3 \sec ^2x -\frac{6 }{\pi })dx$[/tex]<br /> <br /> this is confusing me :S[/tex]
 
That's a definite integral, so that gives you the signed area between the limits of integration, or just a number. What's the derivative of a constant?

A variable (other than x since x would be the dummy variable) in either of the limits of integration would make it a function.
 
hh i already figured that out.. i just took out the 3 and then it becomes tanx - 2/pi x and then its easy..
 

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