Antiderivatives of Logarithmic and Radical Functions: Can They Be Solved?

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Homework Help Overview

The discussion revolves around the evaluation of an improper integral involving logarithmic and radical functions: \(\int^{+\infty}_{0} \frac{\ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{3}}}dx\). Participants explore the challenges of finding the antiderivative and the convergence of the integral.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the difficulty of solving the integral analytically and question the assumptions behind the complexity of the integrand. There are inquiries about alternative methods to determine convergence without calculating the antiderivative.

Discussion Status

The conversation is ongoing, with some participants suggesting the use of asymptotic behavior and the comparison test to analyze convergence. There is no explicit consensus, but productive lines of reasoning are being explored.

Contextual Notes

Some participants express uncertainty about the analytical solvability of the integral and seek resources for further understanding. The original problem's context includes splitting the integral into two parts for analysis.

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Homework Statement


\int \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx

Homework Equations


X.

The Attempt at a Solution


Wolfram Alpha seem to give no answer.
 
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the x2 + 4x makes that impossible to do by analytic means
 


Actually my original problem was determining the convergence or divergence of the following improper integral:
\int^{+∞}_{0} \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx
I split the integral into
\int^{+∞}_{1} \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx
and \int^{1}_{0} \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx
, calculate the antiderivatives, then evaluate the limit of them.
So if I can't calculate the antiderivative, is there any alternative way to see if this integral convergent or not ??
 


Tiny-Tim, how did you know that's impossible to do by analytical means? What should I google to learn more?
 
funcalys said:
Actually my original problem was determining the convergence or divergence of the following improper integral:
\int^{+∞}_{0} \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx
I split the integral into
\int^{+∞}_{1} \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx
and \int^{1}_{0} \frac{ln(x^{2}+4^{x})}{\sqrt{3x^{7}+7x^{^3}}}dx
, calculate the antiderivatives, then evaluate the limit of them.
So if I can't calculate the antiderivative, is there any alternative way to see if this integral convergent or not ??

Do you know how to find the asymptotic behavior of your integrand for x \rightarrow \infty and x \rightarrow 0? If yes, then you may use the comparison test.
 
hi superg33k! :smile:
superg33k said:
Tiny-Tim, how did you know that's impossible to do by analytical means? What should I google to learn more?

it's obvious just from looking at it … that bracket is simply too complicated for any of the known techniques to work! :redface:

once you've had lots of practice at differentiating and integrating, you'll see why :smile:
 
Dickfore said:
Do you know how to find the asymptotic behavior of your integrand for x \rightarrow \infty and x \rightarrow 0? If yes, then you may use the comparison test.

I'll start off. Let us consider the upper bound first. For x \rightarrow \infty. x^2 = o(4^x), so the logarithm in the numerator behaves as \sim x \, \ln(4). Similarly, 7 x^3 = o(3 x^7), so the expression under the square root in the denominator behaves as \sim 3 x^7. Therefore, the integrand behaves as:
<br /> \sim \frac{x \, \ln(4)}{\sqrt{3 x^7}} = \frac{\ln(4)}{\sqrt{3}} \, x^{-5/2}<br />
Do you know whether the integral:
<br /> \int_{1}^{\infty}{x^{-5/2} \, dx}<br />
is convergent or divergent?

A similar analysis can be done on the lower bound of the integral. However, what are the dominant terms in this limit?
 


Thank you very much, I can take it from here :D.
 

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