The sum of two positive integers is 9. What is the least possible sum of their recipricols?
you can do it by listing all the possibilities, that'll show you what the general pattern is.
1/4 + 1/5. The general formala simply says make the numbers as equal as possible.
Oh man! ... mathman..I italic[jus] worked that out!!!...was about to post it!..oh well...:D
OR "given the perimeter of a rectangle, how do you maximize its area?"
A square with each side of length perimeter/4.
I guess you could write 1/x + 1/(9-x) =s, differentiate and set equal to zero getting:
x^2 = (9-x)^2. The maximal value is x=0, and the minimal value is x=4.5, or they are the same. So 4 and 5 are the closest.
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