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## Main Question or Discussion Point

This is a problem I've been working on... I did some things wrong, and syntactically incorrectly, and just messy. Could you help me out? Tell me how I can write this more syntactically correctly, and cleanly, please?

Also, I realize that some might believe this would be more appropriately put in a physics category, however, understand that I'm mainly concerned with the mathematical syntax, at the moment. Thanks.

This is to find Lift or Thrust Force as a function of length and width of propeller or rotor, pitch angle of the blades (assumed to be a constant), and RPM.

At the end, I get Force as a function of Area, which I'm pretty sure must be wrong, since, it seems as length of propeller increases, even with a constant area of propeller blade, force should increase, because average linear velocity along the propeller should increase.

Also, I think the units don't match up at the end,

F = A [RPM π r / (1 min)]^2 D sin(a)

where A=Area, RPM = n revolutions, D = Density of Air, a = pitch angle (assumed to be constant -- I know that they wouldn't be, that will be handled later).

Force of Lift or Thrust on a Spinning Rotor or Propeller:

We start with a "paddle in a river" analogy. A paddle of area, A, is held in a river, with water moving at velocity, v, the paddle held at an angle, a, to the direction of the motion of the water. The water has density, D.

What is the force exerted on the paddle by the water?

m=mass, p=momentum, t=time, F=force, D=density, V=volume, v=velocity, x=distance(in the direction of the water's velocity), A=Area, and a=acceleration in "F=ma" and a=angle in "sin(a)," π=pi

(Area)*(velocity)*(Density) = A(x/t)D = (Volume)D/t = m/t

∴ Av^2D = mv/t = Δp/Δt = F

Note momentum (p) = mv, so Δp/Δt = mΔv/Δt = ma = F

So (adding in sin(a), using the principle of vector components),

F_Lift = A v^2 D sin(a)

Note: this equation does not include a coefficient of friction, drag, or any other losses.

===

Now we need the "average velocity" of the rotor:

v(r) = RPM C(r) / t ; C(r) = 2πr; t=(1 min)

v(r) = RPM 2πr / (1 min)

lim(n→∞) [Ʃ(from r=0 to r_f) RPM 2πdr / (1 min)] / n

v_avg = 1/(r_f - 0) (integral from r=0 to r_f): v(r)dr

= 1/r_f (integral from 0 to r_f): RPM 2 π r dr / (1 min)

= RPM 2 π / [r_f (1 min)] (integral from 0 to r_f): r dr

= RPM π r / (1 min)

substituting "v = RPM π r / (1 min)" into the equation for force,

F = A [RPM π r / (1 min)]^2 D sin(a)

===

F = 4π^2(RPM)^2D/min^2 ∫(0 to r): r^2 w(r) sin[a(r)] dr

if width and angle are not constant

Here are some numbers to use for things like Lift Force, and Air Density. 2000lbs of lift force. And 0.0509 lb/ft^3 for air density.

I also know that it's not going to be 100% efficient. If you want you can put a .7 or .6 or whatever. I haven't looked into that, yet, so I'm not including it, yet.

Thanks so much.

Also, I realize that some might believe this would be more appropriately put in a physics category, however, understand that I'm mainly concerned with the mathematical syntax, at the moment. Thanks.

This is to find Lift or Thrust Force as a function of length and width of propeller or rotor, pitch angle of the blades (assumed to be a constant), and RPM.

At the end, I get Force as a function of Area, which I'm pretty sure must be wrong, since, it seems as length of propeller increases, even with a constant area of propeller blade, force should increase, because average linear velocity along the propeller should increase.

Also, I think the units don't match up at the end,

F = A [RPM π r / (1 min)]^2 D sin(a)

where A=Area, RPM = n revolutions, D = Density of Air, a = pitch angle (assumed to be constant -- I know that they wouldn't be, that will be handled later).

Force of Lift or Thrust on a Spinning Rotor or Propeller:

We start with a "paddle in a river" analogy. A paddle of area, A, is held in a river, with water moving at velocity, v, the paddle held at an angle, a, to the direction of the motion of the water. The water has density, D.

What is the force exerted on the paddle by the water?

m=mass, p=momentum, t=time, F=force, D=density, V=volume, v=velocity, x=distance(in the direction of the water's velocity), A=Area, and a=acceleration in "F=ma" and a=angle in "sin(a)," π=pi

(Area)*(velocity)*(Density) = A(x/t)D = (Volume)D/t = m/t

∴ Av^2D = mv/t = Δp/Δt = F

Note momentum (p) = mv, so Δp/Δt = mΔv/Δt = ma = F

So (adding in sin(a), using the principle of vector components),

F_Lift = A v^2 D sin(a)

Note: this equation does not include a coefficient of friction, drag, or any other losses.

===

Now we need the "average velocity" of the rotor:

v(r) = RPM C(r) / t ; C(r) = 2πr; t=(1 min)

v(r) = RPM 2πr / (1 min)

lim(n→∞) [Ʃ(from r=0 to r_f) RPM 2πdr / (1 min)] / n

v_avg = 1/(r_f - 0) (integral from r=0 to r_f): v(r)dr

= 1/r_f (integral from 0 to r_f): RPM 2 π r dr / (1 min)

= RPM 2 π / [r_f (1 min)] (integral from 0 to r_f): r dr

= RPM π r / (1 min)

substituting "v = RPM π r / (1 min)" into the equation for force,

F = A [RPM π r / (1 min)]^2 D sin(a)

===

F = 4π^2(RPM)^2D/min^2 ∫(0 to r): r^2 w(r) sin[a(r)] dr

if width and angle are not constant

Here are some numbers to use for things like Lift Force, and Air Density. 2000lbs of lift force. And 0.0509 lb/ft^3 for air density.

I also know that it's not going to be 100% efficient. If you want you can put a .7 or .6 or whatever. I haven't looked into that, yet, so I'm not including it, yet.

Thanks so much.