# Applying newtons laws ( Equilibrium)

1. Sep 20, 2008

### sktgurl930

1. The problem statement, all variables and given/known data
A 26.21 kg loudspeaker is suspended 1.15 m below the ceiling by two 3.91-m-long cables that angle outward at equal angles. What is the tension in the cables?

2. Relevant equations
I have no idea

3. The attempt at a solution
well i know that i have the weight which is 26.21 kg and how far its is from the ceiling
and that im trying to find N but i just dont kno wat equation to use but once i find N would i have to divide by 2 since theres 2 cables??

2. Sep 20, 2008

### LowlyPion

Figure what angles the cables make holding the speaker first.

Then draw your vector diagram of the tensions and resolve the x and y components. You know the X direction components must add to 0 and the Y components muust add to the 26.21 kg.

3. Sep 20, 2008

### sktgurl930

ok so would the angles be 17 since they are equal angles??

and i got 17 by making a right triangle with 3.91 being the hypotenuse, and since the speaker is 1.15m away from the ceiling making that one of the sides of the triangle with the right angle.

im i right?? or totally off

4. Sep 20, 2008

### sktgurl930

im not going to lie im teacher isnt very good at teaching
so i have no idea wat ur talkin about with x and y

5. Sep 20, 2008

### LowlyPion

That would be correct. It is 17 degrees. I get 17.1, but that's close enough.

So now you know that 1/2 the weight 26.21kg * 9.8 m/s2 is carried by the vertical component of the tension in the cable. As you noted each cable will carry 1/2.

If that vertical force must be carried in the cable then the tension must be = 1/2 weight/Sine(17).

That treats the Tension as having 2 force components. One vertically (you found) and the other horizontally (given by 26.21*(Cos(17)). When added together as you would add vectors, that adds to the answer you just found. Since the speaker is not in motion, you know that the horizontal components are equal and opposite.

Another way to find the answer would be to recognize that

9.8*26.21*(1/2)/1.15 = Total Tension/3.91

This would be because the definition of Sine is Vertical over hypotenuse and those forces must remain in the same ratio, so ... you can exploit that as the quick way to calculate it as like ratios.

6. Sep 23, 2008

### sktgurl930

thank u and i wish u were my teacher dude ur a life saver!!