Arclength Calculation Process for y=x^3/2, 0<x<5/9

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SUMMARY

The forum discussion focuses on calculating the arclength of the function y = x^(3/2) over the interval 0 < x < 5/9. The correct formula to use is L = √(1 + (dy/dx)²). Participants noted that a common mistake is miscalculating the derivative dy/dx, which is essential for accurate results. The correct derivative for this function is dy/dx = (3/2)x^(1/2), leading to the proper arclength calculation.

PREREQUISITES
  • Understanding of calculus, specifically differentiation.
  • Familiarity with the arclength formula in calculus.
  • Knowledge of the function y = x^(3/2) and its properties.
  • Ability to perform square root calculations and handle algebraic expressions.
NEXT STEPS
  • Review the arclength formula derivation in calculus textbooks.
  • Practice calculating derivatives of polynomial functions.
  • Explore numerical methods for approximating arclengths for complex functions.
  • Learn about the implications of arclength in physics and engineering applications.
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in understanding the arclength calculation process for polynomial functions.

jnimagine
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this is a really easy question... but seems like i keep getting something wrong in my calculations... - -
Find the arclength of y = x^3/2 0<x<5/9
when i do it using the formula; L = sqreroot (1+(dx/dy)^2)
i keep getting one...
can someone post the calculation process...
 
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jnimagine said:
can someone post the calculation process...

Yes...you can:wink:
 

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