Are 3-vectors Defined by Their Transformation Properties?

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3-vectors are defined by their transformation properties with respect to rotations and reflections, rather than Galilean transformations, which pertain to spacetime. Kinetic energy is a scalar under rotations but not under Galilean transformations. Free vectors can be characterized by isometries of space, including rotations and displacements. It is possible to formulate nonrelativistic kinematics using nonrelativistic 4-vectors by taking the limit of Lorentz transformations as the speed of light approaches infinity. This discussion highlights the distinction between spatial and spacetime transformations in defining vector properties.
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Are the usual 3-vectors defined by their transformation properties wrt rotations or Galileian transformations? E.g. kinetic energy would be a scalar wrt rotations but not wrt Galileian transformations.

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Galilean tranformations are transformations of spacetime, not space. Vectors in space can be defined by their transformation properties wrt rotations and reflections. Free vectors which can start at any point can be defined wrt isometries of space, i.e. rotations + displacements.
 
Oh, I see. Could it be possible to formulate nonrelativistic kinematics in terms of nonrelativistic 4-vectors? E.g. just put c->infinity in Lorentz transformations?
 
Yes, the Lorentz transformations become Galilean transformations in the limit c → ∞.
 
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Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...

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