I Are All Triangles Actually Isosceles? Discover My Greek-Euclidean Proof!

  • I
  • Thread starter Thread starter Konstantinos88
  • Start date Start date
  • Tags Tags
    Triangles
AI Thread Summary
The discussion presents a Greek-Euclidean proof claiming that all triangles are isosceles, inviting skepticism about its validity. It references Lewis Carroll's similar fallacious proofs, highlighting the subtlety of the errors involved. Participants engage in analyzing the proof's logic and its implications. The conversation also touches on the translation of the traditional Latin phrase "quod erat demonstrandum" into Greek, confirming their equivalence. The thread emphasizes the enjoyment of dissecting such mathematical arguments while acknowledging the underlying flaws.
Konstantinos88
Messages
2
Reaction score
0
signal-attachment-2019-01-18-234158.jpg


signal-attachment-2019-01-18-234206.jpg


That is my Greek-Euclidean proof that all triangles are isosceles. Any doubts?
 

Attachments

  • signal-attachment-2019-01-18-234158.jpg
    signal-attachment-2019-01-18-234158.jpg
    25.7 KB · Views: 809
  • signal-attachment-2019-01-18-234206.jpg
    signal-attachment-2019-01-18-234206.jpg
    21.5 KB · Views: 715
Mathematics news on Phys.org
Is this different from Lewis Carroll's proof of the same "theorem"?

He had a couple of these fallacious proofs, which are a lot of fun to try to analyze. The error is subtle. I won't spoil the fun yet.

Is your last line in Greek the same meaning as the traditional Latin closing "quod erat demonstrandum" (QED)?
 
RPinPA said:
Is your last line in Greek the same meaning as the traditional Latin closing "quod erat demonstrandum" (QED)?

Yes, exactly this: The phrase, quod erat demonstrandum, is a translation into Latin from the Greek ὅπερ ἔδει δεῖξαι (hoper edei deixai; abbreviated as ΟΕΔ).
https://en.wikipedia.org/wiki/Q.E.D.
 
A nice way to draw the sketch to hide the flaw.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...

Similar threads

Replies
3
Views
2K
Replies
10
Views
2K
Replies
1
Views
2K
Replies
4
Views
2K
Replies
4
Views
2K
Replies
16
Views
974
Replies
2
Views
3K
Replies
3
Views
1K
Back
Top