Are Both Angles in Young's Double Slit Experiment Equal?

AI Thread Summary
The discussion centers on proving that the two angles (θ) in Young's Double Slit Experiment are equal, referencing a diagram from Wikipedia. The user clarifies that the angle in question is the top angle of a triangle depicted in the image, emphasizing the right angle's correctness. They suggest that if two lines are parallel, the angles between them remain equal, and similarly for perpendicular lines. The concept of similar triangles is introduced as a potential method for proving the equality of the angles. The conversation highlights the geometric relationships involved in the experiment's setup.
Physics news on Phys.org
This might help: The small triangle's theta refers to the top angle of the triangle, not the left one. Also, the right angle is right. By that I mean that the angle on the right side of the triangle is a 90 degree angle. This post was an excuse to say that the right angle is right.
 
Yes I was aware of which angles where which. I just used that picture since it was easily attainable. Any hints as to starting this
 
Suppose you have two lines A and B that have angle θ between them.

If you have line C parallel to A, and line D parallel to B, then C and D also have angle θ between them, right?

Likewise, if you have line E perpendicular to A, and line F perpendicular to B, then E and F also have angle θ between them.
 
The phrase 'similar triangles' comes to mind and it hasn't yet been spelled out.
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
Back
Top