Are the Accumulation Points of the Series $(-1)^n/[1 + (1/n)]$ Open at 1 and -1?

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SUMMARY

The series defined by the expression $(-1)^n/[1 + (1/n)]$ for $n \in \mathbb{Z}^+$ has accumulation points at 1 and -1. The discussion confirms that these points are indeed open sets. The values oscillate between -1 and 1, and the limit behavior as $n$ approaches infinity reinforces the conclusion that the accumulation points are correctly identified. Thus, the set of accumulation points is open at both 1 and -1.

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Dustinsfl
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All numbers of the form $(-1)^n/[1 + (1/n)]$, $n\in\mathbb{Z}^+$.

$(-1)^n/[1 + (1/n)] = (-1, 1)$ is that true?
 
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dwsmith said:
All numbers of the form $(-1)^n/[1 + (1/n)]$, $n\in\mathbb{Z}^+$.

$(-1)^n/[1 + (1/n)] = (-1, 1)$ is that true?

For what $n\in\mathbb{Z}^+$ does $-2/3=(-1)^n/[1 + (1/n)]$

CB
 
So the accumulation points are 1 and -1 and the set is open then.
 

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