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All numbers of the form $(-1)^n/[1 + (1/n)]$, $n\in\mathbb{Z}^+$.
$(-1)^n/[1 + (1/n)] = (-1, 1)$ is that true?
$(-1)^n/[1 + (1/n)] = (-1, 1)$ is that true?
The series defined by the expression $(-1)^n/[1 + (1/n)]$ for $n \in \mathbb{Z}^+$ has accumulation points at 1 and -1. The discussion confirms that these points are indeed open sets. The values oscillate between -1 and 1, and the limit behavior as $n$ approaches infinity reinforces the conclusion that the accumulation points are correctly identified. Thus, the set of accumulation points is open at both 1 and -1.
PREREQUISITESMathematics students, educators, and anyone studying real analysis or topology, particularly those interested in sequences and their properties.
dwsmith said:All numbers of the form $(-1)^n/[1 + (1/n)]$, $n\in\mathbb{Z}^+$.
$(-1)^n/[1 + (1/n)] = (-1, 1)$ is that true?