Are Vectors a, b, and c Linearly Independent?

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Homework Help Overview

The discussion revolves around the concept of linear independence in the context of three vectors: a = 2i - 2j, b = 3j - k, and c = i + 2j + k. The original poster seeks clarification on the definition and testing of linear independence as part of a homework problem.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster questions the meaning of 'linearly independent' and the associated test for it. Some participants provide definitions and attempt to set up the equations necessary to explore the linear independence of the vectors.

Discussion Status

Participants are actively engaging with the definitions and mathematical setup required to analyze the vectors. There is an indication of agreement on the approach taken by one participant, but no explicit consensus on the overall understanding of the problem has been reached.

Contextual Notes

The original poster mentions that the problem is from an old exam paper, which may imply constraints related to the context or terminology used in the discussion.

halfoflessthan5
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just a quick one:

Homework Statement


Show that the vectors a=2i -2j, b=3j - k and c = i + 2j +k are linearly independent


Homework Equations





The Attempt at a Solution



What does 'linearly independent' mean and what's the test for it? Its from a really old exam paper so i might just know this theory under a different name.

thankyou :smile:
 
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It means that the equation x*a+y*b+z*c=0 (where x,y,z are scalars and a,b,c are your vectors) has only the trivial solution x=y=z=0.
 
Is this right then:

(2i -2j)x + (3j - k)y + (i + 2j +k)z = 0

multiply out and rearrange

(2x + z)i + (-2x + 3y +2 z)j + (z - y)k = 0

comparing is js and ks on each side

2x + z = 0
-2x + 3y + 2z = 0
z - y = 0

as matrices

[2 0 1] [x] = [0]
[-2 3 2] [y] = [0]
[0 -1 1] [z] = [0]

(like in the eigenvalue problem) there is a non-trivial solution only if determinent of the co-efficients is zero

detM= 12

=/= 0

=> vectors a,b,c where linearly independent
 
Looks right.
 
thankyouuu
 

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