Area between Curves: Find Area Enclosed by y=x-1 and y^2=2x+6

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SUMMARY

The discussion focuses on finding the area enclosed by the line y = x - 1 and the parabola y² = 2x + 6, as presented in Example 6 of James Stewart's "Calculus: Early Transcendentals 6E." The key point is that integrating with respect to x requires splitting the region into two parts due to the symmetry of the parabola along the x-axis. This necessitates calculating two separate integrals: one for the upper part of the curve and another for the lower part, ensuring accurate area computation.

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Homework Statement



Find the area enclosed by the line y = x-1 and the parabola y^2 = 2x+6



The Attempt at a Solution


This is Example 6 in Jame's Stewart Calculus Early Transcentals 6E. I'm trying to figure out why he states that if we were to integrate with respect to x instead of y, then we would have had to split up the region in two pieces.

I'd appreciate it if someone could help clarify that statement.

The link to the example is:

http://books.google.com/books?id=xU...QHNsrzYDw&ved=0CFwQ6AEwCQ#v=onepage&q&f=false
 
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You would have to split the region between the graphs in two pieces mainly because the second equation (y2=2x+6), when solved for y, reveals a symmetry along the x axis. You would have to integrate (-(x-1)+(2x+6).5) between a and b (which you calculate) and 2(0-(-(2x+6).5)) between a and c. With c<b.
 
Last edited:
Thank you! :smile:
 

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