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Homework Help: Finding the area of the loop of the curve y^2=x^3(1-x)^2

  1. Feb 28, 2012 #1
    Find the area of the loop of the curve y^2=x^3(1-x)^2 using integral calculus.

    y=√x^3(1-x)^2
    y=√x^3/2 (1-x)


    To sketch the curve, I assigned values for x and then solved the corresponding values of y.

    x= -1, y= -2
    x= -0.5, y= -0.53
    x=0, y= 0
    x= 0.5, y= 0.177
    x=1, y=0

    how can i find the area of this? >.<
     
  2. jcsd
  3. Feb 28, 2012 #2

    SammyS

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    Hello stardust006. Welcome to PF !

    The ± is important. It gives a clue as to why the graph has a loop.

    There are two x-intercepts. Can you find them ?
     
  4. Feb 28, 2012 #3
    Thank you, I should practice my math T.T
     
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