1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Finding the area of the loop of the curve y^2=x^3(1-x)^2

  1. Feb 28, 2012 #1
    Find the area of the loop of the curve y^2=x^3(1-x)^2 using integral calculus.

    y=√x^3(1-x)^2
    y=√x^3/2 (1-x)


    To sketch the curve, I assigned values for x and then solved the corresponding values of y.

    x= -1, y= -2
    x= -0.5, y= -0.53
    x=0, y= 0
    x= 0.5, y= 0.177
    x=1, y=0

    how can i find the area of this? >.<
     
  2. jcsd
  3. Feb 28, 2012 #2

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    Hello stardust006. Welcome to PF !

    The ± is important. It gives a clue as to why the graph has a loop.

    There are two x-intercepts. Can you find them ?
     
  4. Feb 28, 2012 #3
    Thank you, I should practice my math T.T
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook