Find the area of the loop of the curve y^2=x^3(1-x)^2 using integral calculus.(adsbygoogle = window.adsbygoogle || []).push({});

y=√x^3(1-x)^2

y=√x^3/2 (1-x)

To sketch the curve, I assigned values for x and then solved the corresponding values of y.

x= -1, y= -2

x= -0.5, y= -0.53

x=0, y= 0

x= 0.5, y= 0.177

x=1, y=0

how can i find the area of this? >.<

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# Finding the area of the loop of the curve y^2=x^3(1-x)^2

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