1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Area enclosed by sine and cosine.

  1. Apr 23, 2007 #1
    1. The problem statement, all variables and given/known data

    Hello, i'm trying to find the area enclosed by sine the cosine function on the interval 45 degrees and 225 degrees, my problem is i get a negative number after i do the integration, my answer is -2 root 2.

    here's what i did,

    sin(x)-cos(x)dx

    after integrating,

    cos(x)+sin(x)

    evaluating between 45 degrees and 225 degrees,

    cos(225)+sin(225) - cos(45)-sin(45) (all of which equal -2 root 2 over 2)

    resulting in -4 root 2 over 2 or, -2 root 2
     
    Last edited: Apr 23, 2007
  2. jcsd
  3. Apr 23, 2007 #2
    look at the graph
     
  4. Apr 23, 2007 #3

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    Your signs are wrong on the integral. Eg. the integral of sin(x) is -cos(x).
     
  5. Apr 23, 2007 #4
    oh, darn, i was looking going in a derivative direction (now i feel like i wasted 2 hours) thanks!
     
    Last edited: Apr 23, 2007
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Area enclosed by sine and cosine.
  1. Sine and Cosine (Replies: 1)

Loading...