Artificial Black Holes, again

  • #51
vanesch said:
Yes, but that's highly hypothetical, no ? We already have to live in 10 dimensions...

Maybe you didn't read my other http://news.bbc.co.uk/1/hi/sci/tech/4357613.stm" wherein it's claimed that they've already accomplished it.

The scaling up in itself needs a lot of R&D. You don't see this as spectacular breakthroughs, it are many many small improvements in the reliability of the production process and so on which make up the bulk of this research.

For instance, at PSI I remember having heard a talk about research on back-to-back connections between arrays of photodiodes on silicon and the ASIC that does the data selectioning and compression before sending it on an optical fibre. The industrially available techniques didn't have a high enough density of connection points to do this. So a lot of research was done to improve this, and the density was increased 16 fold.
Now that these back-to-back connections are available, the whole sandwich of photodiodes + electronics is used for high resolution medical X-ray imaging. It took 6-7 years of a 10 person R&D group to devellop this.

There are many such examples.

Sure... fine. But, wouldn't it have been a lot cheaper to just tell these same engineers that we want this or that for other applications? Why not just put them to work building better medical imagers, rather than having to develop the technology secondhand?
 
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  • #52
ubavontuba said:
In order for black holes to form (generally speaking) all of the energy must be expended in the collisions. Glancing blows, that allow for continued momentum of the particles, will not deliver enough energy to compress the particles into black holes. This is why they expect only a small percentage of each run to form black holes.

Problem is, at these energies, protons look more like "a bag of potatoes" than a single particle. So it is relatively hard for that ENTIRE bag to collide coherently without some schrapnels escaping. But if that's a worry, one could slightly "untune" one of the beams wrt the other (say, colliding 7.001TeV protons onto 6.999 TeV protons). Then the center of mass of the collision has enough (1 GeV !) kinetic energy left not to be captured by the Earth's gravity.

Jupiter wasn't always where it is. Besides, Jupiter's moons suffer more tidal forces than the asteroids, and yet there they are.

Damn, never thought of that ! So it MUST be a particle accelerator fired up by an ancient civilisation...
But that means that that black hole is still there ! Help ! :smile: :smile:
 
  • #53
ubavontuba said:
Sure, but the relative motion frame of the two colliding particles is not the same as the relative motion frame of the earth, in this instance.
A particle accelerator accelerates electrons and protons parallal with the Earth's surface (it's locally flat). Therefore, the resultant particles produced also move in the vague direction of parallal to the Earth's surface (sort of spread out in a cone).

The particles hitting the upper atmosphere do anything from a glancing blow, through to aiming right at the centre of the Earth. Therefore the upper atmosphere reactions cover an enormous spectrum of energies (millions of times stronger than CERN) and also aim at every direction from "parallal to the Earth's surface" through to "aim right at the core".

The atmosphere reactions are higher energy and aim all over the place. Hence the danger from them is much much higher than that of CERN, and since we're still here 4.5 billion years after the Earth formed, the chances of a black hole being formed and swallowing us up seems small.
ubavontuba said:
Not true, a rotating body eaten from within would collapse both outwardly and inward. It's a function of angular momentum (like Hawking radiation).
We'd still see the black hole orbiting around by a mysterious force perturbing the asteroids.
ubavontuba said:
Jupiter wasn't always where it is. Besides, Jupiter's moons suffer more tidal forces than the asteroids, and yet there they are.
No, it's been there about as long as the other planets have.

Besides, the strength of tidal forces relates to how big the object is. A tiny moon wouldn't have too much tidal forces on it, or if it formed far from Jupiter than was captured by it's gravity it might be strong enough to survive. If a proto-planet hadn't formed yet, a passing Jupiter might have been enough to shred it and make the asteroids, or shred it into smaller bodies which could survive the tidal forces, giving rise to some of Jupiter's larger moons.

But maybe you're right. Our theories of quantum mechanics and relativity are way off and Earth wasn't the first place in the solar system to develop life, a myterious planet between Mars and Jupiter once harboured life which got destroyed by an artificial black hole when they did 1TeV+ experiments.

That is much more plausable...
 
  • #54
vanesch said:
Problem is, at these energies, protons look more like "a bag of potatoes" than a single particle. So it is relatively hard for that ENTIRE bag to collide coherently without some schrapnels escaping.

Certainly, they expect a spectacular array of parton distribution. Their plan is to collide around a billion particles per second, of which they expect/hope to see a small percentage form nano black holes. It should indeed be a spectacular particle show.

But if that's a worry, one could slightly "untune" one of the beams wrt the other (say, colliding 7.001TeV protons onto 6.999 TeV protons). Then the center of mass of the collision has enough (1 GeV !) kinetic energy left not to be captured by the Earth's gravity.

This is an excellent suggestion, but it would require the loss of some potential energy. I think it'd be a hard sell to the scientists. It'd sure make me happy if they'd modify their experiments thusly, though.

Damn, never thought of that ! So it MUST be a particle accelerator fired up by an ancient civilisation...

Just so we're clear. I did not ever speculate so wildly. All I asked is a question. Specifically: "...how do we know that the asteroid belt wasn't the result of a black hole orbiting the center of mass of a former planet?"

Aren't there rules here against this type of speculation?

But that means that that black hole is still there ! Help ! :smile: :smile:

Perhaps, perhaps not. If a planet didn't collapse around a mini black hole exactly evenly, the mini black hole could easily be flung away in the ensuing melee.
 
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  • #55
AlphaNumeric said:
A particle accelerator accelerates electrons and protons parallal with the Earth's surface (it's locally flat). Therefore, the resultant particles produced also move in the vague direction of parallal to the Earth's surface (sort of spread out in a cone).

Right, but with little or no relative momentum to the Earth's center of mass.

The particles hitting the upper atmosphere do anything from a glancing blow, through to aiming right at the centre of the Earth. Therefore the upper atmosphere reactions cover an enormous spectrum of energies (millions of times stronger than CERN) and also aim at every direction from "parallal to the Earth's surface" through to "aim right at the core".

Sure, but with great relative momentum to the Earth's center of mass. They don't strike the Earth and magically lose their momentum. Remember, momentum is conserved. If they form nano black holes, they'll procede away from or through the earth... friction free.

The atmosphere reactions are higher energy and aim all over the place. Hence the danger from them is much much higher than that of CERN, and since we're still here 4.5 billion years after the Earth formed, the chances of a black hole being formed and swallowing us up seems small.

If you'd just apply basic Newtonian Mechanics to what you are writing, you'd see that regardless of the odds of one forming, the odds of one sticking around are virtually zero. Therefore, this argument is meaningless.

We'd still see the black hole orbiting around by a mysterious force perturbing the asteroids.
No, it's been there about as long as the other planets have.

Not true, the collapse of a planet around a mini black hole isn't necessarily evenly distributed. If a planet didn't collapse around a mini black hole exactly evenly, the mini black hole could easily be flung away in the ensuing melee. The black hole might have a different or eccentric orbit, or might even have achieved solar escape. It'd be so small, It could easily be virtually undectable.

Besides, the strength of tidal forces relates to how big the object is. A tiny moon wouldn't have too much tidal forces on it, or if it formed far from Jupiter than was captured by it's gravity it might be strong enough to survive. If a proto-planet hadn't formed yet, a passing Jupiter might have been enough to shred it and make the asteroids, or shred it into smaller bodies which could survive the tidal forces, giving rise to some of Jupiter's larger moons.

Aren't Jupiter's moon orbits too circular for this to be the case? Don't captured bodies tend to have eccentric orbits? Also, why do the asteroids exist in the wide array of sizes they do then? Shouldn't they be more uniform?

But maybe you're right. Our theories of quantum mechanics and relativity are way off and Earth wasn't the first place in the solar system to develop life, a myterious planet between Mars and Jupiter once harboured life which got destroyed by an artificial black hole when they did 1TeV+ experiments.

That is much more plausable...

See above response to Vanesch.
 
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  • #56
ubavontuba said:
Just so we're clear. I did not ever speculate so wildly. All I asked is a question. Specifically: "...how do we know that the asteroid belt wasn't the result of a black hole orbiting the center of mass of a former planet?"
How do we know it wasn't a vogon destructor fleet?

Or the Klingons?

Or supernova jet that was so narrow as to leave the rest of the solar system unharmed?

Or another Star passing through the solar system disk?

I'm not being wildly speculating, no sirree.

ubavontuba said:
Aren't Jupiter's moon orbits too circular for this to be the case? Don't captured bodies tend to have eccentric orbits? Also, why do the asteroids exist in the wide array of sizes they do then? Shouldn't they be more uniform?

Why do asteroids in exist in a wide array of sizes? Are all rocks equally strong?

Further why would the size of the asteroids be dictated by tidal forces? The planet breaks up due to tidal forces along weak lines in the rock. Why would they be uniform?

Which moons of Jupiter have circular orbits? You mean ALL 63 KNOWN moons of Jupiter have nearly perfect circular orbits? Now that's amazing. 29 of those moons are less than 4 kilometers across. Aside from the Galilean moons and the Amalthea moons (which are only the first 8 and have eccentricities all on the order of 0.001), almost all have eccentricities greater than .15, most greater than .25 and a few as great as .44, one even as great as 0.60. Pluto's eccentricity is only 0.248. Highly circular orbits indeed.
 
  • #57
ubavontuba said:
It'd be so small, It could easily be virtually undectable.

"Virtually" undectable? A borderline case? Tell me, how do you propose to detect an order-of-TeV (10^-24 kg) mass by it's graviational effects? You seem to be missing the essential point here - this is an order-of-magnitude issue. This is 40 orders-of-magnitude from being an issue. Assuming this thing will even exist (huge assumption), and that it won't instantly evaporate (another huge assumption), then we have a totally inert object which will capture particles gravitationally on an astrophysical time scale (assuming it even survives).

Regarding your last post, extremely-relativistic objects do not fall to the earth. Orbital speeds are on order of 10^4 m/s. Relativistic speeds are on order >10^8 m/s. It escapes like a knife through butter.
 
  • #58
Question for the experts - if the black hole is formed from a collision of hadrons, will it interact via the strong force? I can't imagine what qcd looks like in a black hole...
 
  • #59
franznietzsche said:
How do we know it wasn't a vogon destructor fleet?

Or the Klingons?

Or supernova jet that was so narrow as to leave the rest of the solar system unharmed?

Or another Star passing through the solar system disk?

I'm not being wildly speculating, no sirree.

I like your enthusiasm! That's the spirit!

All I'm saying is that the CERN scientists use the evident here-ness of solar system bodies as proof for the safety of this experiment. I'm just pointing out one not-here-ness. I don't see it as being any weaker than their arguments (especially considering that they seemed to forget about the law of conservation of momentum).

Why do asteroids in exist in a wide array of sizes? Are all rocks equally strong?

Further why would the size of the asteroids be dictated by tidal forces? The planet breaks up due to tidal forces along weak lines in the rock. Why would they be uniform?

Ah, then you think it WAS a planet that broke up, versus a void orbit caused by Jupiter's gravity? Sorry, I don't see Jupiter as being capable of actually breaking a planet at that distance. Flinging it away? Maybe. But chopping it into itty bitty pieces?

Which moons of Jupiter have circular orbits? You mean ALL 63 KNOWN moons of Jupiter have nearly perfect circular orbits? Now that's amazing. 29 of those moons are less than 4 kilometers across. Aside from the Galilean moons and the Amalthea moons (which are only the first 8 and have eccentricities all on the order of 0.001), almost all have eccentricities greater than .15, most greater than .25 and a few as great as .44, one even as great as 0.60. Pluto's eccentricity is only 0.248. Highly circular orbits indeed.

Generally speaking, the non-Gallilean moons are quite small and are obviously captured asteroids, as are Mars' moons. Most have retrograde orbits. The Galilean moons orbits are only elliptical due to Laplace resonance. Where's the evidence that they are caused by Jupiter's ability to "shred it (a proposed proto-planet) into smaller bodies which could survive the tidal forces, giving rise to some of Jupiter's larger moons."

How does Io survive these amazing chopping forces of Jupiter?
 
  • #60
Rach3 said:
"Virtually" undectable? A borderline case? Tell me, how do you propose to detect an order-of-TeV (10^-24 kg) mass by it's graviational effects?

Apparently you missed the fact that we were discussing the concept of one eating a planetary core, thus embuing it with some significant mass.

You seem to be missing the essential point here - this is an order-of-magnitude issue. This is 40 orders-of-magnitude from being an issue. Assuming this thing will even exist (huge assumption), and that it won't instantly evaporate (another huge assumption), then we have a totally inert object which will capture particles gravitationally on an astrophysical time scale (assuming it even survives).

That'd be nice, but what about the planetary core's own internal pressure and it's effects?

Regarding your last post, extremely-relativistic objects do not fall to the earth.

Where did I write that?

Orbital speeds are on order of 10^4 m/s. Relativistic speeds are on order >10^8 m/s. It escapes like a knife through butter.

My point exactly. Thereby belying the CERN scientists assumption that the existence of solar objects is proof that no harm can come to us by the creation of artificial nano black holes. If they form natuarally, they don't stick around long enough to cause any harm regardless.
 
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  • #61
ubavontuba said:
I like your enthusiasm! That's the spirit!

All I'm saying is that the CERN scientists use the evident here-ness of solar system bodies as proof for the safety of this experiment. I'm just pointing out one not-here-ness. I don't see it as being any weaker than their arguments (especially considering that they seemed to forget about the law of conservation of momentum).


Ah, then you think it WAS a planet that broke up, versus a void orbit caused by Jupiter's gravity? Sorry, I don't see Jupiter as being capable of actually breaking a planet at that distance. Flinging it away? Maybe. But chopping it into itty bitty pieces?

Ah, then you like putting words in my mouth. You asked why, if a planet was broken by jupiter, wouldn't the asteroids be the same size. I replied to that. I was not stating that I thought a planet formed and was subsequently broken up.


Generally speaking, the non-Gallilean moons are quite small and are obviously captured asteroids, as are Mars' moons. Most have retrograde orbits. The Galilean moons orbits are only elliptical due to Laplace resonance. Where's the evidence that they are caused by Jupiter's ability to "shred it (a proposed proto-planet) into smaller bodies which could survive the tidal forces, giving rise to some of Jupiter's larger moons."

How does Io survive these amazing chopping forces of Jupiter?

Io is literally turning itself inside out because of the tidal, not chopping, forces.

I never supported the comment that captured chunks of rock gave rise to some of Jupiter's larger moons. I object to your comment that 1) Asteroids should suddenly be the same size, and 2) that jupiter's moons mostly have circular orbits.

I think this thread has been just been a progression of greater and greater crackpottery, and should simply be locked.
 
  • #62
franznietzsche said:
Ah, then you like putting words in my mouth. You asked why, if a planet was broken by jupiter, wouldn't the asteroids be the same size. I replied to that. I was not stating that I thought a planet formed and was subsequently broken up.

No, I asked; "Also, why do the asteroids exist in the wide array of sizes they do then? Shouldn't they be more uniform?" in regards to an assumption that a proto-planet hadn't ever formed.

Io is literally turning itself inside out because of the tidal, not chopping, forces.

I never supported the comment that captured chunks of rock gave rise to some of Jupiter's larger moons.

Why do you think I do? That concept came from someone else (AlphaNumeric).

Aside to Alphanumeric: Why haven't the numerous smaller moons formed up into larger ones too?

I object to your comment that 1) Asteroids should suddenly be the same size, and 2) that jupiter's moons mostly have circular orbits.

Where did I write; "Asteroids should suddenly be the same size"? As for circular orbits, I was referring to the "larger" (Galilean) moons mentioned by AlphaNumeric.

I think this thread has been just been a progression of greater and greater crackpottery, and should simply be locked.

I agree. The "experts" here haven't answered any of my questions, and have resorted to crackpot rhetoric to suppress them.
 
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  • #63
ubavontuba said:
Apparently you missed the fact that we were discussing the concept of one eating a planetary core, thus embuing it with some significant mass.
Did you miss the fact, frequently repeated in this thread, that the timescale for 'eating' even a single proton is an astronomical timescale? Or the part where a 10^9 ton black hole was shown to be harmless? (It's also microscopic, if you do the math.)

That'd be nice, but what about the planetary core's own internal pressure and it's effects?
Yes, what about them? We've already mentioned that the mass density is on the order of unity that of solids at STP. I.e., insignificant.

My point exactly. Thereby belying the CERN scientists assumption that the existence of solar objects is proof that no harm can come to us by the creation of artificial nano black holes. If they form natuarally, they don't stick around long enough to cause any harm regardless.
The same argument applies equally well to accelerator-produced black holes. Their mass is SMALL compared to the energies involved, so they must invariably be highly relativistic. Not that it would make any difference.
 
  • #64
Classical GR cross section...


Classical GR Planck Singularity cross-section

m_{Fe} = 9.274 \cdot 10^{-26} \; \text{kg} - Iron nucleon mass (35.1% Terra composition)

m_e - Terra mass
r_e - Terra radius

\tau \sim \frac{1}{n \sigma v}

n_e = \frac{3 m_e}{4 \pi m_{Fe} r_e^3}

\sigma_c = \frac{\pi \hbar G}{c^3}

v_e = \sqrt{\frac{2 G m_e}{r_e}}

\tau_b = \frac{1}{n_e \sigma_c v_e} = \left( \frac{4 \pi m_{Fe} r_e^3}{3 m_e} \right) \left( \frac{c^3}{\pi \hbar G} \right) \left( \sqrt{\frac{r_e}{2G m_e}} \right)

Combining terms:

\tau_b = \frac{4 c^3 m_{Fe}}{3 \hbar} \sqrt{\frac{r_e^7}{2 G^3 m_e^3}}
[/Color]
Reference:
https://www.physicsforums.com/showpost.php?p=1001445&postcount=14
https://www.physicsforums.com/showpost.php?p=1002158&postcount=28
 
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  • #65
Rach3 said:
Question for the experts - if the black hole is formed from a collision of hadrons, will it interact via the strong force? I can't imagine what qcd looks like in a black hole...

If it is a classical black hole, it can only interact through gravity. If it is not a classical black hole, then who's going to say how it interacts...
 
  • #66
ubavontuba said:
My point exactly. Thereby belying the CERN scientists assumption that the existence of solar objects is proof that no harm can come to us by the creation of artificial nano black holes. If they form natuarally, they don't stick around long enough to cause any harm regardless.

Yes, but you're forgetting that this is only ONE of the arguments. Let's put all the arguments in a row:

- first of all, the LHC is not built to make black holes, contrary to what one sometimes might read in speculative articles. However, because the LHC is going to explore higher (a factor 10 about) per nucleon energies, new scenarios are not excluded (one of the reasons to build the machine is to explore a new region of course).

- the energies that will occur in the LHC are much lower than the highest energies occurring naturally in cosmic rays

- in the hypothetical case that black holes might form, normally they should evaporate through Hawking radiation

- in the hypothetical^2 case that Hawking radiation doesn't happen, normally they would have some remnant momentum, by far strong enough to have them escape the Earth's gravity (just as with cosmic ray generated hypothetical black holes)

- in the hypothetical^3 case where they'd form in EXACTLY the center of gravity of the collision (highly unlikely), and Hawking radiation doesn't happen, then they'd be captured by the earth, and they'd eat a proton every year or so according to classical estimations.

People figure that we're now in lala land and that we can take that risk. Others, with safety belts on their sofas, might not agree.
 
  • #67
Rach3 said:
Did you miss the fact, frequently repeated in this thread, that the timescale for 'eating' even a single proton is an astronomical timescale? Or the part where a 10^9 ton black hole was shown to be harmless? (It's also microscopic, if you do the math.)

That's right. Perhaps you missed my first post in this thread wherein I stated we're probably safe. However, that safety is relatively reliant on our theories being correct, and no one really knows that our theories hold true beyond the event horizon. I'm not saying the experiments are inherently dangerous and I'm not saying the experiments shouldn't be conducted. I'd just like the experiments to be performed in a "can't miss" secure way.

Yes, what about them (planetary core's own internal pressure and it's effects)? We've already mentioned that the mass density is on the order of unity that of solids at STP. I.e., insignificant.

Perhaps it is insignificant, perhaps not. Should the nano black hole have the ability to absorb whole particles (not known that they wouldn't), then they'd essentially become a drain in which the internal pressures can fllow into, right?

The same argument applies equally well to accelerator-produced black holes. Their mass is SMALL compared to the energies involved, so they must invariably be highly relativistic. Not that it would make any difference.

Highly relativistic in quantum scales? Don't these two theories come to odds here?
 
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  • #68
vanesch said:
Yes, but you're forgetting that this is only ONE of the arguments. Let's put all the arguments in a row:

- first of all, the LHC is not built to make black holes, contrary to what one sometimes might read in speculative articles. However, because the LHC is going to explore higher (a factor 10 about) per nucleon energies, new scenarios are not excluded (one of the reasons to build the machine is to explore a new region of course).

Really? That's not what the http://www.cerncourier.com/main/article/44/9/22" says. Are they lying then?

- the energies that will occur in the LHC are much lower than the highest energies occurring naturally in cosmic rays

Sure, but why does that matter? According to CERN it doesn't matter because:
CERN Courier said:
It should be stated, in conclusion, that these black holes are not dangerous and do not threaten to swallow up our already much-abused planet. The theoretical arguments and the obvious harmlessness of any black holes that, according to these models, would have to be formed from the interaction of cosmic rays with celestial bodies, mean that we can regard them with perfect equanimity.

Don't you think if conservation of momentum is considered, this argument is generally baseless?

- in the hypothetical case that black holes might form, normally they should evaporate through Hawking radiation

"Should" is not the same as "will".

- in the hypothetical^2 case that Hawking radiation doesn't happen, normally they would have some remnant momentum, by far strong enough to have them escape the Earth's gravity (just as with cosmic ray generated hypothetical black holes)

Maybe, maybe not. Remember they're intent is to make thousands at a time. Can you guarantee that none will not have escape velocity? You, yourself suggested they weaken one beam for an added measure of safety. I concurred.

- in the hypothetical^3 case where they'd form in EXACTLY the center of gravity of the collision (highly unlikely), and Hawking radiation doesn't happen, then they'd be captured by the earth, and they'd eat a proton every year or so according to classical estimations.

How can you so easily trust "classical calculations" with something that's so poorly understood?

People figure that we're now in lala land and that we can take that risk. Others, with safety belts on their sofas, might not agree.

Since the world is shared by all, shouldn't everyone's opinion count?
 
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  • #69
ubavontuba said:
Really? That's not what the http://www.cerncourier.com/main/article/44/9/22" says. Are they lying then?

It's a *hypothetical* article.


Don't you think if conservation of momentum is considered, this argument is generally baseless?

Yes, but the argument ALSO goes for production in an accelerator, because normally, there's no reason why the momentum should come out 0, as there will always be remnants.


Maybe, maybe not. Remember they're intent is to make thousands at a time. Can you guarantee that none will have not have escape velocity? You, yourself suggested they weaken one beam for an added measure of safety. I concurred.

Yes, but it is a silly argument, because the probability of having one with 0 momentum coming out with "untuned" beams is the same as for tuned beams, because no such collision will not have any remnants. So one needs the remnants to perfectly balance in order for the hole to be "at rest" in the lab frame.

How can you so easily trust "classical calculations" with something that's so poorly understood?

Well, if there are scientific arguments AT ALL to say that black holes are to be produced, and if you are using scientific arguments to say that they will eat the earth, then one is allowed to use the same kind of argument to refute it, no ?
If one can use hypothetical arguments (as of now, they ARE hypothetical) to say that black holes are going to be produced in the first place, then why can one NOT use LESS hypothetical arguments to show that they will not cause any harm ? The classical theory of black holes (on which you base yourself to even call them black holes and to even think it might eat the earth) is much more solid than the HYPOTHETICAL arguments that they might be produced (namely the necessity of the universe to be at least 10-dimensional). Hawking radiation, although hypothetical, is nevertheless based upon thermodynamics mixed with some quantum ideas and classical GR, and is as such LESS hypothetical than the theory that says that BH will form in the first place.

Since the world is shared by all, shouldn't everyone's opinion count?

No, only the opinion of people knowing what they talk about should count. Know what ? Two days ago, next to where I'm working, they opened a new research center on nanotechnology, Minatec:
http://www.minatec.com/minatec_uk/index.htm

Well, at the day of its official opening, there have been demonstations by people opposed to it for various hilarious reasons...

http://biotech.indymedia.org/or/2006/05/5127.shtml

I agree that scientists shouldn't be reckless, but one shouldn't be demonstrating against one's own ignorance either, and disrupt the work of people knowing what they are doing.
 
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  • #70
vanesch said:
It's a *hypothetical* article.

Sure, but obviously considered seriously.

Yes, but the argument ALSO goes for production in an accelerator, because normally, there's no reason why the momentum should come out 0, as there will always be remnants
.

Well, according to my research, the impacts have to be nearly perfect for them to obtain the hypothetical nano black hole. If they're perfect and the beams are equal, there really will be no relative momentum to the earth.

Yes, but it is a silly argument, because the probability of having one with 0 momentum coming out with "untuned" beams is the same as for tuned beams, because no such collision will not have any remnants. So one needs the remnants to perfectly balance in order for the hole to be "at rest" in the lab frame.

See above. Also, beam differentials can be sufficient to virtually gaurantee nano black hole escape velocity. That is, they can be tuned to an energy level that would not be sufficient to create nano black holes, if escape velocity is not met. However, this may reduce the energy too much to create them to begin with.

Well, if there are scientific arguments AT ALL to say that black holes are to be produced, and if you are using scientific arguments to say that they will eat the earth, then one is allowed to use the same kind of argument to refute it, no ?
If one can use hypothetical arguments (as of now, they ARE hypothetical) to say that black holes are going to be produced in the first place, then why can one NOT use LESS hypothetical arguments to show that they will not cause any harm ?

Because producing them or not isn't nearly so imporatnt as the consideration of safety. If a young kid is playing with a handgun and he told you he unloaded it, would you believe it to be safe? Assurances of safety aren't always sufficient. The gun may indeed be safe, but are you willing to take the risk?

The classical theory of black holes (on which you base yourself to even call them black holes and to even think it might eat the earth) is much more solid than the HYPOTHETICAL arguments that they might be produced (namely the necessity of the universe to be at least 10-dimensional). Hawking radiation, although hypothetical, is nevertheless based upon thermodynamics mixed with some quantum ideas and classical GR, and is as such LESS hypothetical than the theory that says that BH will form in the first place.

I'd agree wholeheartedly with this, save it's thought they've already done this at the RHIC.

No, only the opinion of people knowing what they talk about should count.

Well I live in a democracy, and in a democracy even the less astute have a say in their fate (as they should).

Know what ? Two days ago, next to where I'm working, they opened a new research center on nanotechnology, Minatec:
[URL]http://www.minatec.com/minatec_uk/index.htm[/url

Well, at the day of its official opening, there have been demonstations by people opposed to it for various hilarious reasons...

http://biotech.indymedia.org/or/2006/05/5127.shtml

Maybe they're hilarious, maybe not. However I feel it is the institution that is responsible for easing the minds of the protesters. Remember, people once thought it was stupid to protest for environmental protections too.

I agree that scientists shouldn't be reckless, but one shouldn't be demonstrating against one's own ignorance either, and disrupt the work of people knowing what they are doing.

But do they? Aren't scientists the first to state that they're conducting these experiments because they DON"T know what will happen?
 
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  • #71
ubavontuba said:
Well, according to my research, the impacts have to be nearly perfect for them to obtain the hypothetical nano black hole. If they're perfect and the beams are equal, there really will be no relative momentum to the earth.

Could you elaborate on this ? You mean it is only when there is entire coherence between the different parton interactions of the two protons that a black hole can form ? This must be a totally coherent diffractive phenomenon ?


See above. Also, beam differentials can be sufficient to virtually gaurantee nano black hole escape velocity. That is, they can be tuned to an energy level that would not be sufficient to create nano black holes, if escape velocity is not met. However, this may reduce the energy too much to create them to begin with.

Well, I have no idea of the precision by which the two beams are equal. But it would be fun if you could work out what would be the needed "untuning" for the COM.
Let's do it:
the mass of two 7 TeV protons colliding is essentally 14 TeV, or
14 TeV * 1.6 10^(-19) / c^2 = 2.5 10^(-23) kg

Giving this mass a velocity of 11200 m/s (escape velocity) comes down to a momentum of this mass of 2.78 10^-19 kg m/s, which is very non-relativistic of course. In eV units, we need to multiply by c and divide by e, to find: 522 MeV untuning is sufficient. I even wonder if they can tune the beams to such an accuracy: we're talking about 0.004% of the total beam energy here.

But do they? Aren't scientists the first to state that they're conducting these experiments because they DON"T know what will happen?

Well, there's a difference between expecting eventually some new stuff to happen, and totally out-of-the-blue catastrophe scenarios, which are on one side BASED upon speculative, and less speculative theories in order to even make the catastrophe scenario initially potentially plausible, but then DENYING the same theories which are then used to show that the catastrophe will not happen, finally.

Why not putting up scenarios for ultrasound ripping apart the spacetime continuum, so that sudden singularities will open up a corridor that enables space invaders to take over earth, and feed on humans ?
I would propose, based upon that, to ban immedately any research on piezo-electric sound transducers...

Honestly, both scenarios sound just as crazy.
 
  • #72
ubavontuba said:
Right, but with little or no relative momentum to the Earth's center of mass.
They are moving at 99.9999% the speed of light, while the Earth is moving at ~0.00001% the speed of light. Is that a big enough different for you? They have LOADS of momentum (for an subatomic object) when taken in the Earth's reference frame! If they didn't, the particle accelerator would be useless, it'd not be accelerating anything!
ubavontuba said:
Remember, momentum is conserved.
No, really? So that was what I should have remembered for my quantum field theory exam last Thursday :rolleyes:
ubavontuba said:
If you'd just apply basic Newtonian Mechanics to what you are writing, you'd see that regardless of the odds of one forming, the odds of one sticking around are virtually zero. Therefore, this argument is meaningless.
So is your about the black holes perhaps to be had at CERN, they've shedloads of momentum to move through the Earth. Even if the colliding beams are untuned by 0.0001% the resultant black hole would sail through the Earth without thinking twice.
ubavontuba said:
Aside to Alphanumeric: Why haven't the numerous smaller moons formed up into larger ones too?
Why would they?
ubavontuba said:
But do they? Aren't scientists the first to state that they're conducting these experiments because they DON"T know what will happen?
That's what experiments are for, to check what we hope will happen will happen. Are you saying any kind of electronic research should be stopped incase the energy involved triggers a castestropic black hole or sends out a signal aliens hear and then come to invade us?

Won't someone think of the children!
 
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  • #73
ubavontuba said:
Highly relativistic in quantum scales? Don't these two theories come to odds here?

No, SR is not in conflict with QM.

Well, according to my research, the impacts have to be nearly perfect for them to obtain the hypothetical nano black hole. If they're perfect and the beams are equal, there really will be no relative momentum to the earth.

You claim to be doing research in string theory...
 
  • #74
Orion1 said:
SpaceTiger, I attempted to setup your equation in post #28, however I obtain a large value for \tau_b?

You're using the conventional Planck length for the horizon radius. TeV mass black holes only appear in theories with extra dimensions that modify the Planck quantities. See here:

https://www.physicsforums.com/showpost.php?p=1001445&postcount=14"
 
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  • #75

Classical GR Terra micro-singularity cross-section:

m_{Fe} = 9.274 \cdot 10^{-26} \; \text{kg} - Iron nucleon mass (35.1% Terra composition)

m_e - Terra mass
r_e - Terra radius
E_b - 1 Tev energy

\tau \sim \frac{1}{n \sigma v}

n_e = \frac{3 m_e}{4 \pi m_{Fe} r_e^3}

r_h = \frac{\hbar c}{E_b}

\sigma_c = \pi \left( \frac{\hbar c}{E_b} \right)^2

v_e = \sqrt{\frac{2 G m_e}{r_e}}

\tau_b = \frac{1}{n_e \sigma_c v_e} = \left( \frac{4 \pi m_{Fe} r_e^3}{3 m_e} \right) \left[ \frac{1}{\pi} \left( \frac{E_b}{\hbar c} \right)^2 \right] \left( \sqrt{\frac{r_e}{2G m_e}} \right)

Combining terms:

\tau_b = \frac{4 m_{Fe}}{3} \left(\frac{E_b}{\hbar c} \right)^2 \sqrt{\frac{r_e^7}{2 G m_e^3}}

\tau_b = 12331.540 \; \text{s} = 3.425 hrs.

m_p - Proton mass
m_{\odot} - Sol mass
r_{\odot} - Sol radius

Classical GR Sol micro-singularity cross-section:
\tau_b = \frac{4 m_p}{3} \left(\frac{E_b}{\hbar c} \right)^2 \sqrt{\frac{r_{\odot}^7}{2 G m_{\odot}^3}}

\tau_b = 15.722 \; \text{s}

Oh no!, micro-singularity radiation has seeded the Earth and the Sun with some black-holes!, we must all evacuate this solar system immediately!

[/Color]
Reference:
https://www.physicsforums.com/showpost.php?p=1001445&postcount=14
https://www.physicsforums.com/showpost.php?p=1002158&postcount=28
https://www.physicsforums.com/showpost.php?p=1004506&postcount=64
 
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  • #76
Orion1 said:
r_h = \frac{\hbar c}{E_b}


Didn't check everything, but this is weird: the hole radius DECREASES with increasing energy ??
 
  • #77

vanesh said:
Didn't check everything, but this is weird: the hole radius DECREASES with increasing energy ??

Affirmative, setting the threshold energy equivalent to the Planck Energy results in a Planck Radius:

r_h = \frac{\hbar c}{E_b}

E_b = E_p

E_b = \sqrt{\frac{\hbar c^5}{G}}

r_h = \hbar c \sqrt{\frac{G}{\hbar c^5}} = \sqrt{\frac{\hbar G}{c^3}}

r_h = r_p

r_h = \sqrt{\frac{\hbar G}{c^3}}

This is called a 'quantum black hole'.

According to my research, the Planck Mass is the maximum producible mass of a 'quantum black hole'. Meaning that any particle accelerator or cosmic event within this quantum threshold is not capable of generating a more massive quantum singularity, except by spherical absorption or accretion.

Interesting to note, that if 'quantum black holes' can exist as naked singularities, then a Planck Mass can also exist as a naked singularity.
[/Color]
 
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  • #78
Orion1 said:
Affirmative, setting the threshold energy equivalent to the Planck Energy results in a Planck Radius:

Ah, yes, understood ; you adapt G in the classical formula of a BH in order for the Planck energy to come out equal to 1 TeV. Yes, then the schwarzschild radius is indeed the Planck radius (up to a factor 2 I think).

Next point, your tau_b is the time constant needed to EAT ONE SINGLE IRON NUCLEUS, right ? So this BH eats one single iron atom every 3 hours, if I'm not mistaking ? (and on the sun, one proton every 15 seconds).

Not so worrysome, right ?
 
  • #79
Why don't neutrons or protons behave like mini black holes? Can matter get even denser than a single neutron or proton?
 
  • #80
This is a very entertaining thread, in the funny nothing of consequence sort of way! :rolleyes: It has been like daytime television. I can read page one, then come back later and read page 6, and I have not missed a beat! Anecdotal arguments, lucky for us, are not sufficient to cease all fundamental high energy physics in the world. It reminds me of the people who thought we would set the Earth's atmosphere on fire by detonating a nuclear device. By the way, when the great name of "string theory" is invoked, which of the five mathematically self consistent versions are you referring to? The one that we have a chance at doing experiments to support? Wait, that doesn't answer the question does it, still left with five. :wink:

This is all in good fun of course, no offense is intended towards anyone! :smile:
 
  • #81
Jeff Reid said:
Why don't neutrons or protons behave like mini black holes? Can matter get even denser than a single neutron or proton?
electrons/positrons are "denser".
:smile:
 
  • #82
tehno said:
electrons/positrons are "denser".
:smile:
OK, can a single electron exhibit the behaviour of a very tiny black hole? Hmm, they do capture and release photons.
 
  • #83

\tau_b is the 'mean time' interval for nuclear reaction occurence or the time required to absorb 1 particle. This is the amount of time required for a single quantum black hole to reaction with a single iron nucleus or with a single proton.

The 'particle reaction rate' is the reciprocal of the 'mean time'.

\lambda_b = \frac{1}{\tau_b} = \frac{dn}{dt}

\lambda_b = \frac{dn}{dt} = \frac{3}{4 m_{Fe}} \left(\frac{\hbar c}{E_b} \right)^2 \sqrt{\frac{2 G m_e^3}{r_e^7}}

Based upon this particle rate, and presuming this rate is constant, how much time would be required for a single quantum black hole to consume 1 m^3 of Terra?

t_a = \frac{n_e}{\lambda_b} = \frac{1}{\sigma_c v_e} = \frac{1}{\pi} \left( \frac{E_b}{\hbar c} \right)^2 \sqrt{\frac{r_e}{2 G m_e}}

t_a = \frac{1}{\pi} \left( \frac{E_b}{\hbar c} \right)^2 \sqrt{\frac{r_e}{2 G m_e}}

t_a = 7.309 \cdot 10^{32} \; \text{s m}^{-3} - 2.317*10^25 years*m^-3

Based upon this particle rate, and presuming this rate is constant, how much time would be required for a single quantum black hole to consume Terra?

n_t = \frac{m_e}{m_{Fe}}

t_e = \frac{n_t}{\lambda_b} = \left( \frac{m_e}{m_{Fe}} \right) \frac{1}{\lambda_b}

t_e = 7.951 \cdot 10^{53} \; \text{s} - 2.521*10^46 years

[/Color]
Reference:
https://www.physicsforums.com/showpost.php?p=1005179&postcount=75
 
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  • #84
Orion1 said:
\tau_b is the 'mean time' interval for nuclear reaction occurence or the time required to absorb 1 kg.

This is then a strange notation, because:

(density x sigma x velocity) is normally the rate, per unit of time, of ONE SINGLE INTERACTION (of which there are "density" items per unit of volume).
 
  • #85
vanesh said:
your tau_b is the time constant needed to EAT ONE SINGLE IRON NUCLEUS, right ? So this BH eats one single iron atom every 3 hours, if I'm not mistaking ? (and on the sun, one proton every 15 seconds).

(density x sigma x velocity) is normally the rate, per unit of time, of ONE SINGLE INTERACTION (of which there are "density" items per unit of volume).

Affirmative, that is correct.
\lambda = n \sigma v

t_e = \frac{4}{3} \left(\frac{E_b}{\hbar c} \right)^2 \sqrt{\frac{r_e^7}{2 G m_e}}

t_e = 7.951 \cdot 10^{53} \; \text{s} - 2.521*10^46 years

[/Color]
Reference:
https://www.physicsforums.com/showpost.php?p=1005179&postcount=75
 
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  • #86
The Planck mass...

However, the multiple dimensions postulated by string theory would make gravity many orders of magnitude stronger at small distances. This has led some string theorists to predict micro black hole production at upcoming colliders.

Current predictions for the behavior of a black hole with a mass less than Planck mass are inconsistent and incomplete.

I am enquiring as to what the string theory predicted 'orders of magnitude stronger' value is for G at small distances?

m_p - Proton mass

Gravitational Coupling Constant:
\alpha_g = \frac{G m_p^2}{\hbar c}

Gravitational 'Constant':
G = \frac{\hbar c \alpha_g}{m_p^2}

Strong Gravitational Coupling Constant:
\alpha_g = 1

Strong Gravitation:
G_s = \frac{\hbar c}{m_p^2} = 1.130 \cdot 10^{28} \; \text{Nm}^2 \text{kg}^{-2}
t_e = \frac{4}{3} \left(\frac{E_b}{\hbar c} \right)^2 \sqrt{\frac{r_e^7}{2 G_s m_e}}
t_e = 6.110 \cdot 10^{34} \; \text{s} - 1.937*10^27 years

Combining terms:
t_e = \frac{4 m_p E_b^2}{3} \sqrt{\frac{r_e^7}{2 m_e (\hbar c)^5}}
[/Color]
Reference:
http://en.wikipedia.org/wiki/Quantum_black_hole
http://hyperphysics.phy-astr.gsu.edu/hbase/forces/couple.html
 
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  • #87
If they were able to make a small black hole, and it got "loose" and fell to the center of the Earth, the pressures at the Earths core would force material into it so fast that even a very small one would gobble us up very fast. I am not sure what the exact pressure is at the Earths core but it could force material through even a very small "hole" very quickly. I do agree that once it gobbled up the Earth, it would just continue to orbit the Sun, and the Moon would still orbit the black hole as if it were the Earth...
 
  • #88
IMP said:
If they were able to make a small black hole, and it got "loose" and fell to the center of the Earth, the pressures at the Earths core would force material into it so fast that even a very small one would gobble us up very fast. I am not sure what the exact pressure is at the Earths core but it could force material through even a very small "hole" very quickly. I do agree that once it gobbled up the Earth, it would just continue to orbit the Sun, and the Moon would still orbit the black hole as if it were the Earth...


No, you should read this thread.

First of all, a black hole that falls to the center of the earth, wouldn't stop there, but would continue falling up on the other side, just to plunge in again, and on and on, because there's no "friction" on the black hole.

Second, there have been posted in this thread a lot of calculations of the speed at which it would gobble up matter.
Don't forget that the black hole we're talking about here IS MUCH MUCH SMALLER THAN A PROTON. As such, pressures on *atomic* level (such as in the center of the earth) matter little: the black hole travels most of the time in the empty space between nucleae.
A way to calculate the probability of hitting a nucleus (and somehow imagining that it would gobble up the entire nucleus, which is MUCH MUCH bigger than the black hole itself - which is a worst-case scenario) is done by calculating the "cross section" of the black hole and its probability to cross a nucleus on its voyages through the earth. We know its speed (just falling), and knowing the cross section and the density of nucleae, we can estimate how many nucleae it could eat per unit of time.

For a classical black hole, the calculation is done in the link provided by Pervect in this post:
https://www.physicsforums.com/showpost.php?p=1001414&postcount=12

for a MUCH LARGER black hole, about the size of a proton, weighting a billion tons (figure that! A black hole *the size of a proton* weights a billion tonnes ; we're talking here about black holes that weight 10 TeV or 10^(-24) kg - go figure how small it is !)

For more exotic calculations which are more severe, orion made some, and arrived at a time to eat the Earth ~ 10^46 years.

All this in the following rather un-natural hypotheses:
- no Hawking radiation (which would make the black hole evaporate almost immediately)
- production of black hole EXACTLY IN THE CENTER OF GRAVITY of the collision (no remnant particles)
- very high production rate, producing billions of black holes per second.
 
  • #89
Hi guys. Just a few quick questions:

Your calculations seem to be based on a constant rate of absorption, is this right? Wouldn't the absorption rate increase exponentially? In your cross section, are you looking only at the Schwarzschild radius? Doesn't gravity extend far beyond? Someone mentioned that the scientists failed to mention the effect that conservation of momentum has on nanoblackholes. Is that right? If they missed this very basic concept what else might they be missing?
 
  • #90

wikipedia said:
Current predictions for the behavior of a black hole with a mass less than Planck mass are inconsistent and incomplete.

One problem with calculating a constant rate of absorption, is the fact that a quantum black hole's horizon radius decreases with increasing mass. Therefore the horizon radius becomes a function of its mass:

r_h(E_b) = \frac{\hbar c}{E_b}

This means that the cross section and reaction rate decreases as the quantum black hole mass increases.

However, I can determine what the upper limit of my equation is:

E_b = E_e = m_e c^2

r_h = \frac{\hbar}{m_e c}

t_e = \frac{4m_p}{3} \sqrt{\frac{(m_e c)^3 r_e^7}{2 \hbar^5}}

t_e = 6.874 \cdot 10^{131} \; \text{s} - 2.180*10^124 years

An exponentially decreasing reaction rate should be even longer than this.

An equation demonstrating an exponentially decreasing cross section and reaction rate would probably show that the time required to absorb the Earth is infinite.

Is this infinite?, close enough...
[/Color]
 
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  • #91
MelissaSweet said:
Hi guys. Just a few quick questions:
Your calculations seem to be based on a constant rate of absorption, is this right? Wouldn't the absorption rate increase exponentially?

Yes, that is correct, but it won't change the conclusion very much (it will change the result by a few orders of magnitude).
As has been exposed (see link by pervect), even a billion ton black hole would need 10^28 years to eat the earth. But first, our nano 10^(-24) kg black hole needs to grow to a billion ton black hole and will thus have to eat about ~10^38 atoms. It is still smaller than the size of a proton during all that time.
The more pessimistic calculation by Orion (using more dimensions, and hence a higher effective G constant for the nano black hole) would become rather complicated, because this effective G constant would SHRINK as the nano black hole grows, and leaves its "quantum domain" to become more and more a classical black hole. So although its mass would increase, its effective cross section wouldn't rise proportionally.

In your cross section, are you looking only at the Schwarzschild radius? Doesn't gravity extend far beyond?

Yes, but the "cross section" is the quantified probability of ABSORPTION, not simply of interaction. The moon interacts gravitationally with the earth, but isn't ABSORBED by the earth. So anything much farther away from the BH than the Schwarzschild radius will simply undergo a deflection (talking classically). This interaction is extremely small: don't forget that outside of the Schwarzschild radius, the gravitational effect of a BH is the same as any other mass. So you'd get the gravitational attraction of a mass of 10^(-24) kg, which is normally utterly neglegible.

Also, there has been made a crude assumption: that is, when a nano black hole encounters an iron nucleus, that it eats the ENTIRE nucleus, even though the nano BH is much much much smaller than the nucleus. But this is probably entirely wrong: it would only eat at most a gluon or a quark, meaning that it would leave most of the mass of the nucleus behind (which would probably undergo a desintegration into another nucleus and a few pions or so).


Someone mentioned that the scientists failed to mention the effect that conservation of momentum has on nanoblackholes. Is that right? If they missed this very basic concept what else might they be missing?

No, the point was something different. Some people argued that eventual nano black holes produced in cosmic rays (of much higher energy than the LHC accelerator will produce) have high momentum wrt the earth, and hence will just fly once through the earth, so the fact that these collisions are regularly happening is no proof that nano black holes aren't dangerous.
That reasoning is correct: indeed, even if we underwent showers of nanoblack holes, they would at most eat one or two iron atoms before having traveled through the Earth and fly off in the blackness of space.
So the observation that cosmic rays exist, is no proof of the "safety" of nanoblack holes, is entirely correct.

However, the reasoning ALSO applies to the eventual nanoblack holes produced at the LHC. It is only in the case that they are produced in the exact center of gravity of the two colliding particles that they don't have any momentum left and hence fall to the earth. But this is a highly exceptional case, because colliding protons, at these energies, must rather be seen as the collision of two bags of potatoes, the real interactions being between the potatoes (quarks and gluons), and not between the entire bags. So normally, such collisions produce a lot of "debris" together with an interesting interaction (such as the production of a nano BH). It is what renders the experimental observation a pain in the a**: between miriads of uninteresting tracks in one and the same event, you have to find those three or four tracks which indicate something interesting. There is a priori no reason for any correlation between the debris, and the interesting interaction (this has already been established for many years in lower-energy interactions ; I did my PhD on part of the problem for instance). So there is no reason to assume that this interaction happens in the center of gravity of the bag of potatoes, it is rather in the center of gravity of the two potatoes who do the interaction. Now, this center of interaction usually has high momentum wrt the center of gravity of the interacting protons, so the resultant product (in casu a nano BH) also.
In that case, it flies right off the reaction event, through the earth, or through the sky, into outer space.

And, honestly, the possibility that all these exotic processes happen (only predicted by very exotic and speculative theories) is way more dubious than the (also speculative, but way more down to earth) prediction that Hawking radiation really happens. In fact, all these speculative theories which open the possibility of the production of nano BH, ALSO predict Hawking radiation.

And if this is true, a nano black hole will go POOF even before leaving the detector.

So the entire reasoning is flawed. Current established physics says that NO black holes will be produced at the LHC. One needs to switch to speculative theories to open up even their possibility. And those same speculative theories (just as well as a small extrapolation of currently established physics) foresee Hawking radiation. So it is a bit aberrant to speculate on the production of nano BH using these theories, and refute them at the same time when considering Hawking radiation, no ?
 
  • #92
vanesch said:
No, the point was something different. Some people argued that eventual nano black holes produced in cosmic rays (of much higher energy than the LHC accelerator will produce) have high momentum wrt the earth, and hence will just fly once through the earth, so the fact that these collisions are regularly happening is no proof that nano black holes aren't dangerous.

I'm going to have to disagree on this point. True, most of the black holes produced by cosmic rays would escape, but you must realize that every time there is an event, many many many particles are produced in the shower (~10^11, from what I've read). I would imagine that since these events happen millions of time a year across the globe, at least one black hole would come out of a collision with a small enough kinetic energy as to not escape the Earth's gravitational pull. So, coupled with the fact that a black hole takes so long to become the size of a single proton, it's POSSIBLE that there are some floating in and out of the Earth right now, as we speak.
 
  • #93
Hi again, my friends and I came up with a few more questions. We hope they're not too naive: :smile:

Vanesch said:
Yes, but the "cross section" is the quantified probability of ABSORPTION, not simply of interaction. The moon interacts gravitationally with the earth, but isn't ABSORBED by the earth. So anything much farther away from the BH than the Schwarzschild radius will simply undergo a deflection (talking classically). This interaction is extremely small: don't forget that outside of the Schwarzschild radius, the gravitational effect of a BH is the same as any other mass. So you'd get the gravitational attraction of a mass of 10^(-24) kg, which is normally utterly neglegible.

Isn't your angular momentum effect limited by the Earth's own angular momentum? Therefore wouldn't classical gravity work to grow the nanoblackhole because mass falls to the center of the Earth in a classical way?

No, the point was something different. Some people argued that eventual nano black holes produced in cosmic rays (of much higher energy than the LHC accelerator will produce) have high momentum wrt the earth, and hence will just fly once through the earth, so the fact that these collisions are regularly happening is no proof that nano black holes aren't dangerous.
That reasoning is correct: indeed, even if we underwent showers of nanoblack holes, they would at most eat one or two iron atoms before having traveled through the Earth and fly off in the blackness of space.
So the observation that cosmic rays exist, is no proof of the "safety" of nanoblack holes, is entirely correct.

So that snubabooba guy was right? Isn't that scary by itself?

However, the reasoning ALSO applies to the eventual nanoblack holes produced at the LHC. It is only in the case that they are produced in the exact center of gravity of the two colliding particles that they don't have any momentum left and hence fall to the earth. But this is a highly exceptional case, because colliding protons, at these energies, must rather be seen as the collision of two bags of potatoes, the real interactions being between the potatoes (quarks and gluons), and not between the entire bags. So normally, such collisions produce a lot of "debris" together with an interesting interaction (such as the production of a nano BH). It is what renders the experimental observation a pain in the a**: between miriads of uninteresting tracks in one and the same event, you have to find those three or four tracks which indicate something interesting. There is a priori no reason for any correlation between the debris, and the interesting interaction (this has already been established for many years in lower-energy interactions ; I did my PhD on part of the problem for instance). So there is no reason to assume that this interaction happens in the center of gravity of the bag of potatoes, it is rather in the center of gravity of the two potatoes who do the interaction. Now, this center of interaction usually has high momentum wrt the center of gravity of the interacting protons, so the resultant product (in casu a nano BH) also.
In that case, it flies right off the reaction event, through the earth, or through the sky, into outer space.

We seem to agree that colliding bags of potatoes might be very messy but the largest mess would occur at the center of the interaction. Are you saying this isn't right?

And, honestly, the possibility that all these exotic processes happen (only predicted by very exotic and speculative theories) is way more dubious than the (also speculative, but way more down to earth) prediction that Hawking radiation really happens. In fact, all these speculative theories which open the possibility of the production of nano BH, ALSO predict Hawking radiation.

And if this is true, a nano black hole will go POOF even before leaving the detector.

That's reassurring but isn't it also speculative? We read the article about the possible nanoblackhole at the RHIC. Do you have more information on it? Was it observed to completely evaporate? Did it leave the detector?

So the entire reasoning is flawed. Current established physics says that NO black holes will be produced at the LHC. One needs to switch to speculative theories to open up even their possibility. And those same speculative theories (just as well as a small extrapolation of currently established physics) foresee Hawking radiation. So it is a bit aberrant to speculate on the production of nano BH using these theories, and refute them at the same time when considering Hawking radiation, no ?

We don't know we're just college students. We think ignoring problems is stupid but we don't know enough to think about this critically. We're wondering if the scientists are similarly handicapped. Snubbabubba apparently found a weakness in their arguments. Can we safely assume they're right otherwise? :smile:
 
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  • #94
MelissaSweet said:
That's reassurring but isn't it also speculative? We read the article about the possible nanoblackhole at the RHIC. Do you have more information on it? Was it observed to completely evaporate? Did it leave the detector?

Which article?

Most people only read Wilczek's first essay on this and that's all they get, while ignoring a second paper that analyzed this in detail and came to the conclusion that "...The authors estimate the parameters relevant to black-hole production and find that they are absurdly small..."[1] So what black hole? How could it leave a detector when it doesn't even have any appreciable chance of being formed in the first place? And the fact that RHIC's stuctural integrity hasn't changed since Day 1 is ample proof that these black holes never occured.

Zz.

1. R.L. Jaffe et al., Rev. Mod. Phys. v.72, 1125 (2000).
 
  • #95
Guillochon said:
I'm going to have to disagree on this point. True, most of the black holes produced by cosmic rays would escape, but you must realize that every time there is an event, many many many particles are produced in the shower (~10^11, from what I've read). I would imagine that since these events happen millions of time a year across the globe, at least one black hole would come out of a collision with a small enough kinetic energy as to not escape the Earth's gravitational pull. So, coupled with the fact that a black hole takes so long to become the size of a single proton, it's POSSIBLE that there are some floating in and out of the Earth right now, as we speak.

True. One should indeed compare the "integrated luminosity" of 4 billion years of cosmic rays with 10 years of LHC operation.
 
  • #96
MelissaSweet said:
Isn't your angular momentum effect limited by the Earth's own angular momentum? Therefore wouldn't classical gravity work to grow the nanoblackhole because mass falls to the center of the Earth in a classical way?

I don't understand a word if what you're saying :confused:

So that snubabooba guy was right? Isn't that scary by itself?

No, he wasn't right, because that's by far not the entire argument.
In fact, the argument of the high-energy cosmic ray collisions was used for ANOTHER potential catastrophe: the phase-transformation of the vacuum.
According to certain theories, our vacuum is just one of many possible, and maybe not even the most stable one. Just as with supercooled water, a "seeding event" might induce a phase transformation. A high energy collision might just do that, and blow the entire universe as we know it, apart (making it go through a phase change). So switching on the LHC might just blow the universe apart... and it was against THIS argument that it was argued that many more high energy collisions occur every day in cosmic rays without the universe blowing apart.
It wasn't an argument against that other catastrophe on small scale: the black hole that eats the earth.
We seem to agree that colliding bags of potatoes might be very messy but the largest mess would occur at the center of the interaction. Are you saying this isn't right?

Indeed, this isn't right. It may sound strange, but at high energies, the potatoes in the bag have different energies and momenta (although they all move at essentially lightspeed). So individual potatoe-potatoe collisions all have entirely different centers of gravity (this is where the potatoe bag analogy breaks down in fact - so it was probably not appropriate to use it in the first place, my appologies). In the real potatoe bag, there's a relationship between the momenta of the potatoes and their energies, because they all have to go at the same "bag speed". But relativisitically, this doesn't hold anymore (the bag goes essentially at light speed, as do all the components). So it is as if there were *independent* potatoes flying around. As such, you see that the center of gravity of the potatoe potatoe collisions has nothing to do with the center of gravity of the bag-bag collisions.

That's reassurring but isn't it also speculative? We read the article about the possible nanoblackhole at the RHIC. Do you have more information on it? Was it observed to completely evaporate? Did it leave the detector?

I don't know the details. Me thinks that if they have some indication of it, that is in the data of the remnants (the Hawking explosion). Because otherwise *they wouldn't have noticed it*. It would not have left the slightest trace in the detector (at most eaten up one or 2 atoms of the detector material).

We don't know we're just college students. We think ignoring problems is stupid but we don't know enough to think about this critically. We're wondering if the scientists are similarly handicapped. Snubbabubba apparently found a weakness in their arguments. Can we safely assume they're right otherwise? :smile:
[sarcastic mode on]

Of course not. Scientists are a dangerous lot, wanting to destroy the world in their quest for fame :biggrin: :biggrin: Most of the time, they don't have kids themselves, and are blinded by their silly faith in their own ideas. We should all put them in camps ! :cool:

(uh, not so irrealistic, what I write, in fact :-p )
 
  • #97
Sorry guys, we tried to come up with some good questions but I guess not. Would you guys be so kind as to remove my posts? Um would you remove your responses too?
 
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  • #98
MelissaSweet said:
Sorry guys, we tried to come up with some good questions but I guess not. Would you guys be so kind as to remove my posts? Um would you remove your responses too?

Eh, no, what would be the point of a forum if each time one should remove questions and responses ?
 
  • #99
SpaceTiger said:
The most it could do is take the nucleon's entire mass, but realistically, it would probably only take a fraction of the total mass energy -- perhaps a quark or gluon.

vanesch said:
it would only eat at most a gluon or a quark, meaning that it would leave most of the mass of the nucleus behind (which would probably undergo a desintegration into another nucleus and a few pions or so).

Strong Gravitation:
(Quantum BH strong nuclear reaction with a proton)
t_p = \frac{4 E_b^2}{3} \sqrt{\frac{m_p r_p^7}{2 (\hbar c)^5}}

t_p = 3.362 \cdot 10^{-16} \; \text{s}
[/Color]
 
  • #100
Orion1 said:
Strong Gravitation:
(Quantum BH strong nuclear reaction with a proton)
t_p = \frac{4 E_b^2}{3} \sqrt{\frac{m_p r_p^7}{2 (\hbar c)^5}}

t_p = 3.362 \cdot 10^{-16} \; \text{s}
[/Color]

Yes, but that is only when the BH is *gravitationally captured* by the proton (as it was gravitationally captured by the earth)...
 
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