Artificial gravity in a washing machine

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SUMMARY

The discussion focuses on calculating the artificial gravity experienced by clothes in a washing machine drum with a radius of 26 cm spinning at 4 revolutions per second. Participants clarify that the centripetal acceleration formula, ac = v2/r, should be used, where velocity is converted to meters per second and angular velocity to radians per second. The correct approach involves using the formula ac = rω2, leading to a calculated acceleration that should then be expressed as a multiple of gravitational acceleration (g = 9.8 m/s2). Misunderstandings about centrifugal versus centripetal acceleration are also addressed.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula
  • Knowledge of angular velocity and its conversion to radians per second
  • Familiarity with gravitational acceleration (g = 9.8 m/s2)
  • Basic skills in unit conversion (cm to m, rev/s to m/s)
NEXT STEPS
  • Research the derivation and application of the centripetal acceleration formula
  • Learn about angular velocity and its significance in rotational motion
  • Explore the concept of artificial forces in non-inertial reference frames
  • Investigate practical applications of centripetal acceleration in everyday appliances
USEFUL FOR

Students studying physics, engineers designing rotating machinery, and anyone interested in the mechanics of washing machines and rotational dynamics.

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Homework Statement



If a washing machine's drum has a radius of 26 cm and spins at 4 rev/s, what is the strength of the artificial gravity to which the clothes are subjected? Express your answer as a multiple of g.

Homework Equations



w = distance/time
w= (angular velocity)

The Attempt at a Solution


I basically changed the units. (cm to m) and ( rev/sec to rad/sec) and tried to solve for w and dividing by 9.8. However this is not the answer. I am not sure I am even on the right track to solve the question. please help
 
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You want to find the acceleration of the clothes.

Centripetal acceleration is defined as

ac=v2/r

So the velocity in metres/second divided by the radius.

You get the centripetal acceleration, and that should do it. What it's really asking for is centrifugal acceleration, but in reality there's no such thing. Centrifugal acceleration is an artificial force that only exists in accelerating reference frames.
 
So i did v2/r and I divided that number by 9.8 since it asks for a multiple of G. I did not get the answer. I also do not understand why you say it should be centripedal and not centrifugal
 
Well for your purposes you should use centrifugal. I'm just saying that in reality there's no such thing.

Also, that's odd. Are you sure you used metres per second?
 
yea
the definition for acp=r w2
so i got .026m * (25.132rad/sec)2 = 16.422
then i divided that number by 9.8...it didn't work :(
any ideas??
 
So, you are getting the gravity of a washing machine? I don't think there is an specific gravity of a washing machine. But maybe with the help of formula, you can get it's gravity.
 

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