Aspect ratio of cylinder floating in water?

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jayjay112
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Aspect ratio of cylinder floating in water?

Hi,

Basically the question is:

What is the aspect ratio (h/d) for a cylinder of specific gravity 0.65 above which it will float vertically? (Note use GM = I/V - BG)
So i found a solution that is simliar and can help solve the problem. (please see attached)

Using this information would the ans be:

H/d = 0.65/sqrt(8 x 0.65)

I think the main problem is i don't fully understand the specific weights.

where it says h = specific weight /specific weight 2 x H

should specific weight /specific weight 2 be = 0.65

hope this makes sense thank you for your help
 
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