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Aspect ratio of cylinder floating in water?

  1. Feb 15, 2010 #1
    Aspect ratio of cylinder floating in water???

    Hi,

    Basically the question is:

    What is the aspect ratio (h/d) for a cylinder of specific gravity 0.65 above which it will float vertically? (Note use GM = I/V - BG)
    So i found a solution that is simliar and can help solve the problem. (please see attached)

    Using this information would the ans be:

    H/d = 0.65/sqrt(8 x 0.65)

    I think the main problem is i dont fully understand the specific weights.

    where it says h = specific weight /specific weight 2 x H

    should specific weight /specific weight 2 be = 0.65

    hope this makes sense thank you for your help
     

    Attached Files:

  2. jcsd
  3. Feb 16, 2010 #2
    Re: Aspect ratio of cylinder floating in water???

    Please let me know if I am being too vauge.
     
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