Atomic Spectrum of an Unknown Element

Click For Summary
SUMMARY

The discussion centers on identifying an unknown element based on the emitted x-ray wavelength of 0.0897 nm when an electron transitions from the M shell (n = 3) to the K shell (n = 1). The initial conclusion points to Selenium (atomic number 34) using the equation E = 1240 / λ. However, the correct approach involves using effective nuclear charge (Zeff) rather than the atomic number (Z), leading to confusion and incorrect calculations. The participant highlights the need for Moseley's equation to accurately determine the element in multi-electron systems.

PREREQUISITES
  • Understanding of atomic structure and electron shells
  • Familiarity with Bohr's model of the atom
  • Knowledge of effective nuclear charge (Zeff)
  • Proficiency in using Moseley's law for x-ray emission
NEXT STEPS
  • Study Moseley's law and its application in identifying elements
  • Learn about effective nuclear charge (Zeff) and its calculation
  • Explore the limitations of Bohr's theory in multi-electron systems
  • Investigate the relationship between wavelength and energy in x-ray emissions
USEFUL FOR

Chemistry students, physicists, and educators focusing on atomic theory, x-ray spectroscopy, and element identification techniques.

XianForce
Messages
16
Reaction score
0

Homework Statement



When an electron drops from the M shell (n = 3) to a vacancy in the K shell (n = 1), the measured wavelength of the emitted x-ray is found to be 0.0897 nm. Identify the element.

Homework Equations



E = 1240 / λ
E = (-13.6 / n^2) * (Zeff^2)

The Attempt at a Solution


According to my homework, the answer is Selenium (atomic number = 34). I initially got that answer by using: (-13.6 / 9) * Z^2 + (13.6 / 1) * Z^2 = 1240 / (.0897). Solving for Z here, I got 33.8.

But I then learned that we are supposed to use Zeff, and not simply Z. I must be misunderstanding something though, because I would then think that the equation would be:

(-13.6 / 9) * (Z - 10)^2 + (13.6 / 1) * Z^2 = 1240 / (.0897)

because there are 10 electrons in the first and second energy levels, so I thought this equation would account for that. But I keep getting a Z value around 32.7 with this which would be in between Germanium and Arsenic.

So what am I missing?
 
Physics news on Phys.org
The first thing about this problem is : Bohr's theory and his equations are not even valid here. This is not a one-electron system.

As to how one does this, I am guessing Moseley's equation is the most valid.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
Replies
11
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
3K