Attempt: How to Calculate Acceleration in Pulley Systems

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starprincess
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Hello Everyone,
I am having difficulty with these selected problems. Attached is a link to the diagram in reference to each problem. I would truly appreciate your help! Thank you!

1. In Fig.1 the scale at the left is attached to the ceiling and a mass of 1.00 kg hangs from it. It reads 9.81 N. The identical scale at the right is connected by perfect strings passing over perfect pulleys to two 1.00 kg masses hanging vertically at the end of the strings. The scale at the right reads:
a) exactly 9.81 N
b) more than 9.81 N, but not quite as much.
c) less than 9.81 N.
d) exactly 19.81 N.
e) more than 19.62 N.

http://i82.photobucket.com/albums/j246/starprincess101/DSC01143.jpg"

Attempt: I believe this has something to do with static equilibrium equation and the use of tension? So I am guessing it would be A.2. Two identical masses are attached by a light string that passes over a small pulley, as shown in Fig.2. The table and the pulley are frictionless. The masses are moving:
a) with an acceleration less than g.
b) at constant speed.
c) with an acceleration greater than g.
d) with an acceleration equal to g.

Attempt: I think it would be constant speed.http://i82.photobucket.com/albums/j246/starprincess101/DSC01144.jpg" 3. Two masses are connected by a string which goes over an ideal pulley as shown in Fig. 3. Block A has a mass of 3.00 kg and can slide along a rough plane inclined 30.0 degrees to the horizontal. The coefficient of the kinetic friction between block A and the plane is 0.400. Block B has a mass of 2.77 kg. What is the acceleration of the blocks?
a) 0.392 m/s2
b) 1.96 m/s2
c) 3.12 m/s2
d) 5.35 m/s2
e) 0

Attempt: I have no idea how to solve this problem or where to start because I have never learned about inclinations yet.

http://i82.photobucket.com/albums/j246/starprincess101/DSC01145-1.jpg"
 
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In problem one, the two scales are doing exactly the same job. The weight on the left pulley is holding the scale while the weight on the right pulls on it with 9.81 N. You might think it would read 2x9.81 in both cases because there is 9.81 pulling on each end, but the scale is designed to read just 9.81 N.

For problem 2, you must do some calculations. Think of the two masses and the string as one object that may have an acceleration to the right and down (always in the direction of the string).
The sum of the forces in the direction of the string must equal ma.
Have a go at it - add up all the forces acting that way and put " = ma" on the end!
Show us what you get and we'll check it out for you.