Auxiliary Field H Problem, Asks for Magnetic Field etc

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laz0r
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Homework Statement



Diagram of a hollow cylinder with a circular cross-section cut through its end, with arrows showing current flowing along its length, next to a homework problem about conduction current density in a hollow copper cylinder.



Homework Equations



int[H*dl] = I fenc

∇×H = cr^2 [Khat]

∇×H = Jf


The Attempt at a Solution



The textbook I have been assigned (griffiths) only deals with currents that are uniformly distributed and I'm not sure how to go about calculating the free enclosed current for the problem. If I knew how to do that, this problem would be very easy.

Using an amperian loop that extends the radius of the cylinder

∫(closed)H*dl = I fenc

|H|[2*pi*s] = I fenc
H = I fenc / [2*pi*s] [phi hat direction]

Then I would use the cross product ∇×H = Jf in order to calculate Jf, sub in Jf = cr^2 and then solve for c, thus solving part a. I'm just not sure about how to calculate the free enclosed current. if anyone knows the proper formula for this problem I would be grateful to see it.
 
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  • Textbook problem 4 about a hollow copper cylinder with inner radius a and outer radius b, carrying current I0 with current density proportional to r squared, followed by parts a and b, with a diagram of a hollow cylinder with arrows showing current flow.
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Hi laz0r. Welcome to PF!

Regarding finding the proportionality constant c: If you integrate Jfree over the cross-sectional area (a<r<b) what should that equal?
 
Ah ok, I understand now. INT[J*dA] = Ifree, then you can use that for your H field later on and find the expression for c immediately by rearranging.
 
laz0r said:
Ah ok, I understand now. INT[J*dA] = Ifree, then you can use that for your H field later on and find the expression for c immediately by rearranging.

You should be able to get c from just ∫J[itex]\cdot[/itex]dA = Io