Average magnitude of force during a 0.4 second impact

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SUMMARY

The discussion centers on calculating the average magnitude of force exerted on a roof by a 40kg branch falling from a height of 5.5m over an impact duration of 0.4 seconds. The participant used the momentum formula P=mv to find the momentum (P) to be approximately 415 kg·m/s. Dividing this momentum by the impact time of 0.4 seconds yields an average force of 1037.5 Newtons, which is confirmed as correct by other participants in the discussion.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of momentum (P=mv)
  • Basic principles of free fall and gravitational force
  • Ability to perform unit conversions and calculations involving time and force
NEXT STEPS
  • Study the concept of impulse and its relation to force and time
  • Learn about energy conservation in free fall scenarios
  • Explore advanced applications of Newton's laws in collision physics
  • Investigate the effects of different materials on impact force absorption
USEFUL FOR

Students in physics, educators teaching mechanics, and anyone interested in understanding the dynamics of falling objects and impact forces.

Crushgear64
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Homework Statement



A 40kg branch falls 5.5m and lands on a roof. The roof withstood the the impact.

Homework Equations



If the impact time was 0.4 second calculate the magnitude of the average force exerted on the roof during the impact.

The Attempt at a Solution



F=ma doesn't seem right because it's in free fall though.
P=mv ≈ 415
415/0.4=1037.5N?

Is this right?
 
Last edited:
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Crushgear64 said:

Homework Statement



A 40kg branch falls 5.5m and lands on a roof. The roof withstood the the impact.

Homework Equations



If the impact time was 0.4 second calculate the magnitude of the average force exerted on the roof during the impact.

The Attempt at a Solution



F=ma doesn't seem right because it's in free fall though.
P=mv ≈ 415
415/0.4=1037.5N?

Is this right?
That is correct !
 

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