Average Percentages over 3 years

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The discussion focuses on calculating the average percentage increase in a town's population over three years. The population grew from 1,000,000 in 2006 to 1,200,000 in 2007 (20% increase) and to 1,800,000 in 2008 (50% increase). The correct method for finding the average percentage increase is through the geometric average, which results in a 34% average growth per year. This approach contrasts with the arithmetic average, which would incorrectly suggest a 35% average. The geometric average is essential for accurately reflecting compounded growth over multiple periods.
Dollydaggerxo
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I am just having trouble with percentages.

Lets say a town has a population of

1,000,000 in 2006
1,200,000 in 2007
1,800,000 in 2008

The percentage increase from
2006-2007 is 20%
2007-2008 is 50%

So, what I want to work out is the AVERAGE percentage per year.

The increase from 2006 to 2008 is 80%. So would it be 80%/2=40% per year?

OR

Would it be (20%+50%)/2 =35%

Neither of these actually give the right answer if you do 1,000,000*1.4^2, so was just wondering if this was even possible?
 
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Since you know the the average squared must equal the growth over the two years, taking he square root of the growth will give you the average. Now you just need to observe that the two year growth is the product of the two yearly growths: 1.2 \cdot 1.5 = 1.8, so avg = \sqrt {1.2 \cdot 1.5} = 1.34. So, 34% average growth.

This type of average is called geometric, as opposed to the more familiar arithmetic average.
 
Hi,

(1+x)^2=1,8
x=1,8^(0,5)-1=0,3416
34,16% of average augmentation each years
 
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