1. The problem statement, all variables and given/known data In the circuit of Figure 4-2, let N1=2000 turns, N2=1000 turns, R=0, Z1=0 and ZL=300+j400 (Ω). If V1(max)=1500 V, what is the average power delivered to ZL? A. 5400 W B. 2700 W C. 337.5 W D. 675 W 2. Relevant equations V2=(N2/N1)V1 3. The attempt at a solution since turn factor is 2:1 then V2= (1/2)V1=750V. and I2=750/(300+j400)= 0.9-1.2i=1.5A (magnitude of polar form) here is where i get confused. my book for some examples uses (1/2)I2R for power, however i also know the general power equation is I2R. in this case i decided to go with the book's example so to find average power to ZL I used (1/2)I2R and only used resistive part of ZL in calculating power: 1/2 (1.5)2*(300) = 337.5. so i put C as my answer.