Bad Math Jokes

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SUMMARY

The forum discussion centers around humorous and clever math jokes, showcasing a variety of puns and anecdotes that blend mathematics with comedy. Participants share jokes related to mathematical concepts such as the Ackermann function, knot theory, and topology, emphasizing the playful side of mathematics. Notable jokes include the classic "Why is 6 afraid of 7? Because 7 8 9" and a pun involving Lie algebras. The conversation highlights the community's appreciation for both math and humor, making it a lighthearted exchange among enthusiasts.

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  • Understanding of basic mathematical concepts such as functions and topology.
  • Familiarity with mathematical humor and puns.
  • Knowledge of notable mathematical figures and theories, including the Ackermann function and knot theory.
  • Awareness of popular culture references in mathematics, such as "Doctor Who" and classic comedy routines.
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  • Explore the Ackermann function and its implications in computational theory.
  • Research knot theory and its applications in mathematics and physics.
  • Investigate the concept of topology and its significance in modern mathematics.
  • Learn about the history and impact of mathematical humor in educational contexts.
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Mathematicians, educators, students, and anyone interested in the intersection of mathematics and humor will benefit from this discussion. It serves as a lighthearted resource for those looking to engage with math in a fun and entertaining way.

  • #331
Nothing in the tax code requires that we operate in base 10.

So I calculate my income in Hexadecimal.
 
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  • #332
Ivan Seeking said:
Nothing in the tax code requires that we operate in base 10.

So I calculate my income in Hexadecimal.
They may send you a response in binary Esperanto.
 
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  • #333
BillTre said:
They may send you a response in binary Esperanto.
I will need Bill Shatner!
 
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  • #334
If I ever get caught I will just tell them I've done a lot of programming. It's an easy mistake to make.
 
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  • #335
1736350583807.png
 
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  • #336
The New Math...

1736355127553.png


 
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  • #337
472735196_1047322564078612_5196476120040524529_n.jpg
 
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  • #338
1736447064511.png
 
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  • #339
1737131966962.png
 
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  • #340
Given a matrix: " And the Eigenvalues are Real?".
" Yes, the Eigenvalues are Real, but their names were changed to protect the innocent."
 
  • #341
A little Medic humor... :smile:

1738600187083.png
 
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  • #342
berkeman said:
A little Medic humor... :smile:

View attachment 356759
One could even that this insight, is power-ful
 
  • #343
berkeman said:
A little Medic humor...
Is that a gold-plated deformed rebar I see, held before me?
 
  • #345
Topologist, responding to accusations: " Yes, I slept with your wife. But up to Homotopy, she's my wife too."
 
  • #346
WWGD said:
Topologist, responding to accusations: " Yes, I slept with your wife. But up to Homotopy, she's my wife too."
Bold. It means he knows they have the exact same number of piercings.
 
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  • #347
Orodruin said:
Bold. It means he knows they have the exact same number of piercings.
I doubt your average Math prof's wife will have piercings that can't be smoothed out.
 
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  • #348
Orodruin said:
Bold. It means he knows they have the exact same number of piercings.
So probably not Jane Pierce.
 
  • #349
jbriggs444 said:
So probably not Jane Pierce.
Didn't see any references on her having piercings, certainly not non-trivial ones.
 
  • #351
New Math Logic book:
" Ultraproducts, America's New Supermodel".
 
  • #352
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  • #353
etotheipi said:
If 2005 humour is still funny... the English cat 'one two three' and the French cat 'un deux trois' had a swimming race to decide after which country the Channel should be named. The un deux trois cat sank.
Ahh, un deux trois quartre cinq
 
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  • #354
DrGreg said:
All numbers are equal! Let ##a## and ##b## be any two numbers and define$$
c = a + b.
$$Multiply both sides by ##a-b##:$$
(a - b)c = (a - b)(a+b).
$$Expand:$$
ac - bc = a^2 - b^2.
$$Rearrange:$$
b^2 - bc = a^2 - ac.
$$Add ##ab## to both sides:$$
ab + b^2 - bc = a^2 + ab - ac.
$$Factorise:$$
(a+b-c)b = (a+b-c)a.
$$Cancel:$$
b=a
$$QED.
Nope, because C = A + B, so
A+B-C = 0,
Let's see.

c = a + b.
$$Multiply both sides by ##a-b##:$$
(a - b)c = (a - b)(a+b).
$$Expand:$$
ac - bc = a^2 - b^2.
$$Rearrange:$$
b^2 - bc = a^2 - ac.
$$Add ##ab## to both sides:$$
ab + b^2 - bc = a^2 + ab - ac.
$$Factorise:$$
(a+b-c)b = (a+b-c)a. = 0xB = 0xA
$$Cancel:$$
b=a
$$QED.
 
  • #355
Re Pde's, the song " Looking for love in all the wrong places, looking for love in Sobolev spaces.
 
  • #356
Screenshot 2025-03-01 at 10.41.38 AM.png
 
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  • #357
Screenshot 2025-03-14 at 10.42.01 AM.png
 
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  • #358
An old car chuggs up a hill of 1 mile for an average speed of 15 mph.
The car then travels downhill for 1 mile.
What must the downhill speed be, so that for the whole trip the average speed is 30 mph.

Ludicrous Speed
 
  • #359
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  • #360
1000120434.jpg
 
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