Balancing chemical equations polystomics and H2O + CO2/NO2

  • Thread starter Thread starter AMan24
  • Start date Start date
  • Tags Tags
    Chemical
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
AMan24
Messages
58
Reaction score
2

Homework Statement



(NH4)2S + HNO3 = ? - main problem

LiHCO3 + HClO = ? - check just in case problem

Homework Equations


None.

The Attempt at a Solution


I think it has to equal H2S + NH4NO3
Or H2S + NO2 + H2O

I've used multiple online chemical balancing calculators and they all give me different answers.

There's also the 2nd problem which I'm 99% sure on but just to be sure. I think it equals

LiClO + H2O + CO2
 
Last edited:
Physics news on Phys.org
AMan24 said:
I think it has to equal H2S + NH4NO3

Sounds reasonable as a first approximation (although it depends a bit on the level - sulfides can be oxidized by the nitric acid, making things more complicated). Note - correct identification of the products doesn't mean the reaction equation is balanced.

Reaction of the carbonate with acid is very similar. No, there is no LiClO produced (actually hypochlorite is typically written as LiOCl).
 
  • Like
Likes   Reactions: AMan24
Borek said:
Sounds reasonable as a first approximation (although it depends a bit on the level - sulfides can be oxidized by the nitric acid, making things more complicated). Note - correct identification of the products doesn't mean the reaction equation is balanced.

Reaction of the carbonate with acid is very similar. No, there is no LiClO produced (actually hypochlorite is typically written as LiOCl).

I meant to write LiHCO3 + HOCl = LiOCl + H2O + CO2
Instead of LiHCO3 + HCl = LiOCl + H2O + CO2

And thanks for the help
 
AMan24 said:
I meant to write LiHCO3 + HOCl = LiOCl + H2O + CO2

This one is actually much more complicated, as HOCl is a weak acid. No idea what kind of answer is expected (on some level the one you gave can be OK, even if technically it is not correct). But - unless you have already learned about equilibrium calculations - you shouldn't worry.
 
  • Like
Likes   Reactions: AMan24