Balancing torques, static equalibrium

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The discussion focuses on a physics problem involving a uniform rod in static equilibrium, supported by a tensioned string. The downward torque is correctly identified as (L/2)Mg sin theta, while the need to balance this with the upward torque from the tension is emphasized. Participants discuss how to determine the perpendicular distance from the pivot point to where the tension acts. The tension in the supporting string is derived from balancing these torques, leading to the conclusion that T = mg/2. Understanding the relationship between the torques is crucial for solving the problem.
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Homework Statement



A uniform rod of mass M sticks out from a vertical wall and points toward teh floor. If the smaller angle it makes with the wall is theta, and its far end is attached to teh ceiling by a string parallel to the wall, find the tension in the supporting string.

Homework Equations


ok I know that this involves balancing torques and the object is in static equalibrium.
this is a MCAt style question so I'm giving multiple choice answers, I know the answer to the question, but I wasn't sure how it was derived.



The Attempt at a Solution



I know that my downward torque based on the rod is (L/2)Mg sin theta. since net torque is 0, the CCW torque must balance the CW torque, but how does this make T = mg/2?
 
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Bu2009 said:

Homework Statement



A uniform rod of mass M sticks out from a vertical wall and points toward teh floor. If the smaller angle it makes with the wall is theta, and its far end is attached to teh ceiling by a string parallel to the wall, find the tension in the supporting string.

Homework Equations


ok I know that this involves balancing torques and the object is in static equalibrium.
this is a MCAt style question so I'm giving multiple choice answers, I know the answer to the question, but I wasn't sure how it was derived.



The Attempt at a Solution



I know that my downward torque based on the rod is (L/2)Mg sin theta. since net torque is 0, the CCW torque must balance the CW torque, but how does this make T = mg/2?
Hi BU2009 and welcome to PF,

Your downward torque is correct. Now consider your upward torque, provided by the tension. At what [perpendicular] distance does this tension act from the pivot (wall)?
 
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