Ball sliding on 3d-inclined plane

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SUMMARY

The discussion revolves around determining the time (t) it takes for a solid ball to roll down a 3D inclined plane with an elevation angle Θ. Two methods were employed: one using rotational dynamics and linear kinematics, yielding the equation t = √(14L/5g sinΘ), and the other using conservation of energy, resulting in t = √(10L/7g sin Θ). The discrepancy in results was clarified by recognizing that the acceleration is affected by friction, leading to the conclusion that the correct approach must account for frictional forces in the calculations.

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  • Understanding of rotational dynamics equations
  • Familiarity with linear kinematics equations
  • Knowledge of conservation of energy principles
  • Basic concepts of friction and its impact on motion
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  • Learn about the derivation of rotational dynamics equations
  • Explore advanced kinematics problems involving inclined planes
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terryds
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Homework Statement



http://www.sumoware.com/images/temp/xzdmdjtlksnfhiqc.png
A solid ball rolls perfectly with initial velocity v0 in horizontal axis ( y-axis ) on an inclined plane with elevation angle Θ as the picture above shown. This ball moves turning due to the gravitational acceleration till it has traveled distance L in x-axis when it's at the bottom of the plane.
Determine the time (t) the ball needs to get to the bottom of the plane ! (The ball doesn't slip while rolling)

Homework Equations


Rotational dynamics equation and linear kinematics equation
Or conservation of energy equation

The Attempt at a Solution



I have two methods to solve the problem. But, the answers are different.

Using rot. dynamics equation and linear kinematics.
I just consider the x-axis since it's what the question asks.
ΣFx = ma
mg sin Θ - f = ma (Note : f is friction force)
f = mg sin Θ - ma

Στ = I α
f R = I α
f R = I (a/R)
(mg sin Θ - ma) R = (2/5) m R^2 (a/R)
mg sin Θ - ma = (2/5) m a
g sin Θ - a = (2/5) a
(7/5) a = g sin Θ
a = (5/7) g sin Θ

Then, I use the kinematics equation
L = 0.5 a t^2
2L/a = t^2
14L/ (5g sin Θ) = t^2
t = √(14L/5g sinΘ)

But, using conservation of energy, I get different answer
m g sin Θ L = (1/2) m v^2 + (1/2) I ω^2
m g sin Θ L = (1/2) m v^2 + (1/2) (2/5 m R^2) (v^2 / R^2)
g sin Θ L = (1/2) v^2 + (1/5) m v^2
g sin Θ L = (7/10) v^2
v = √(10 g sin Θ L / 7 )

Then, I use the kinematics
vt = vox + a t
√(10 g sin Θ L / 7 ) = 0 + g sin Θ t
t = √(10L/7g sin Θ)


Which one is correct? Why?
 
Last edited by a moderator:
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terryds said:

Homework Statement



http://www.sumoware.com/images/temp/xzdmdjtlksnfhiqc.png
A solid ball rolls perfectly with initial velocity v0 in horizontal axis ( y-axis ) on an inclined plane with elevation angle Θ as the picture above shown. This ball moves turning due to the gravitational acceleration till it has traveled distance L in x-axis when it's at the bottom of the plane.
Determine the time (t) the ball needs to get to the bottom of the plane ! (The ball doesn't slip while rolling)

Homework Equations


Rotational dynamics equation and linear kinematics equation
Or conservation of energy equation

The Attempt at a Solution



I have two methods to solve the problem. But, the answers are different.

Using rot. dynamics equation and linear kinematics.
I just consider the x-axis since it's what the question asks.
ΣFx = ma
mg sin Θ - f = ma (Note : f is friction force)
f = mg sin Θ - ma

Στ = I α
f R = I α
f R = I (a/R)
(mg sin Θ - ma) R = (2/5) m R^2 (a/R)
mg sin Θ - ma = (2/5) m a
g sin Θ - a = (2/5) a
(7/5) a = g sin Θ
a = (5/7) g sin Θ

Then, I use the kinematics equation
L = 0.5 a t^2
2L/a = t^2
14L/ (5g sin Θ) = t^2
t = √(14L/5g sinΘ)

But, using conservation of energy, I get different answer
m g sin Θ L = (1/2) m v^2 + (1/2) I ω^2
m g sin Θ L = (1/2) m v^2 + (1/2) (2/5 m R^2) (v^2 / R^2)
g sin Θ L = (1/2) v^2 + (1/5) m v^2
g sin Θ L = (7/10) v^2
v = √(10 g sin Θ L / 7 )

Then, I use the kinematics
vt = vox + a t
√(10 g sin Θ L / 7 ) = 0 + g sin Θ t
t = √(10L/7g sin Θ)


Which one is correct? Why?

Oops.. I think that I forgot that the acceleration is not g sin theta since there is friction.. ( I used a = g sin theta in using the kinematics )
Problem Solved :)
 
Last edited by a moderator:

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