Balmer series experiment

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The discussion centers on understanding the parameters needed for the Balmer series experiment, specifically the variables n, θ, and d. The user seeks clarification on how to find the wavelength (λ) without knowing the value of d. It is confirmed that d, the distance between diffraction grating lines, can be calculated as 1/300 mm given the grating has 300 lines per millimeter. This information is essential for proceeding with the calculations related to the experiment. The conversation emphasizes the importance of understanding the relationship between these variables in the context of diffraction.
MatinSAR
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Homework Statement
Canculate ##\lambda## using information you have.
Relevant Equations
##n\lambda=d\sin\theta##
Hello. In data that the professor sent, I see only ##n## and ##\theta##. So I do not know what is d. Can I find ##\lambda## without it?
1713286318515.png


On other thing he mentioned :
Suppose that the diffraction grating consists of 300 lines per millimeter.

I know that d is the distance between two consecutive diffraction grating lines, but I don't know if it has anything to do with what my teacher said.

Can I say that for one line that passes through the diffraction grating d is 1/300 mm ?
 
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Sure you can. This is why he gave you this information.
 
nasu said:
Sure you can. This is why he gave you this information.
@nasu Thank you.
 
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My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...
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