Baseball Velocity and Components: Solving for Final Velocity and Height

  • Thread starter Thread starter Tycho
  • Start date Start date
  • Tags Tags
    Stupid
AI Thread Summary
To solve for the baseball's final velocity, angle, maximum height, and velocity components, it's essential to determine the initial speed, which can be assumed to be around 10 m/s, although this is considered slow. Given the ball travels 30 meters in 3 seconds, the initial speed must exceed 30 m/s, as it covers more distance due to its vertical motion. The horizontal component of the initial velocity can be calculated using the formula v = d/t, while the vertical component can be derived from the motion equations, considering the ball's peak height. The assumption that the initial and final speeds are equal holds true when neglecting air resistance. Accurate calculations will yield the desired parameters for the baseball's trajectory.
Tycho
Messages
23
Reaction score
0
I'm not quite sure how to get started on this problem...

a baseball is struck by a bat, and 3 seconds later it is caught 30m away.

now the questions ask for it's final velocity, it's angle as it left the bat, the greatest height it reached, and the X and Y components of it's velocity as it was hit.
all of these things i can do if i had the speed of the ball initially. is it safe to assume that it is traveling at 10 m/s?
 
Physics news on Phys.org
to find the X component of the initial velocity use v=d/t for the whole loop. To find the Y component of the initial velocity use V(final)-V(initial)=gt for half of the loop. I said half of the loop because you're looking at the velocity when the ball goes up in the air so that would take 1.5 seconds and on top the velocity is 0. After that, use vector addition to find the initial starting velocity and the angle.
 
I took a look at this website:

http://www.baseball-almanac.com/articles/fastest-pitcher-in-baseball.shtml

There is a list of the fastest pitchers in baseball. The speed range is 100-103 mph. So, let's consider a 100 mph pitch. We have

100 \frac{\mbox{miles}}{\mbox{hour}} \left( \frac{1,609.3 \mbox{ m}}{1 \mbox{ mile}} \right) \left( \frac{1 \mbox{ hour}}{3600 \mbox{ s}} \right) \approx 44.7 \frac{\mbox{m}}{\mbox{s}}

You're probably safe with v_i \leq 44.7 \frac{\mbox{m}}{\mbox{s}}.

A 10 \frac{\mbox{m}}{\mbox{s}} pitch is slow, but you can use it.
 
Tycho said:
I'm not quite sure how to get started on this problem...

a baseball is struck by a bat, and 3 seconds later it is caught 30m away.

now the questions ask for it's final velocity, it's angle as it left the bat, the greatest height it reached, and the X and Y components of it's velocity as it was hit.
all of these things i can do if i had the speed of the ball initially. is it safe to assume that it is traveling at 10 m/s?

If you take advantage of the fact that you know how long it flew, you should be able to determine the intial speed of the ball. In fact, since you're ignoring air resistance, it's the same as the final speed.

Perhaps you can figure out what the horizonal component of the ball's inital velocity.

P.S. Since the ball goes up and down during it's flight, it's traveling more than 30 meters. Since it's traveling more than 30 meters in 3 seconds, it's got to have started with a speed of more than 30 meters per second.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top