Basic Capacitors: What Happens When a Thick Slab is Inserted?

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Inserting a thick slab of metal between the plates of a parallel-plate capacitor, while keeping it parallel and not in contact, alters the capacitance by effectively creating two capacitors in series. The electric field inside the metal slab becomes zero due to charge redistribution, which cancels any external electric field. Consequently, the capacitance can be calculated by considering the two gaps created on either side of the slab. This configuration results in a change in the overall capacitance value, as the system now behaves differently than a single capacitor. Understanding these principles is essential for grasping the underlying physics of capacitors.
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The question I had was more qualitative than quantitative, but I always preferred to understand concepts in both ways clearly. Can someone explain what happens to the capacitance of parallel-plate capacitor when a thick slab of metal is inserted between the plates, parallel to them but not in contact with them? I'm having trouble going through the algebra of it all.

~~Thanks!
 
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hi michael650! :smile:
michael650 said:
Can someone explain what happens to the capacitance of parallel-plate capacitor when a thick slab of metal is inserted between the plates, parallel to them but not in contact with them?

the https://www.physicsforums.com/library.php?do=view_item&itemid=6"

the electric field E is zero inside the metal (because it's a conductor, and the charges rearrange themselves to cancel out any external field), and D0 in the two gaps …

so the capacitance is … ? :smile:

(of course, you could just say that it's now two capacitors in series, with the same charge :wink:)
 
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on the metal slab free charge would come to the surface to make the E field inside the slab 0 since it is a conductor . Tiny tim submitted his when i was typing this .
 
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