Basic chemistry: sulphur dioxide shape??! I realize this isn't homework, but it's so basic I'm ashamed of putting it in the chemistry section. I'm trying to self-teach here, but my textbook is awful and I'm even worse. Question: Workout the shape of SO2. Step 1: Draw lewis diagram to work out how lone pairs and bonds are arranged. That's my first problem. I can't figure out how in high heaven the funny dots fits together in a way that works. Resigned, I improvise step 2 Step 2: Go onto wikipedia and discover that SO2 is structured O=S=O. Problem #2. Since when did sulphur get 10 electrons in the valence shell?? Ignoring the lone pair apparently in limbo I finish the question. Step 3: 2 double bonds → 2 electron clouds → a linear molecule. Checking the answers, SO2 is bent. Apparently, I should have counted the 5th pair. :grumpy: So ultimately my question is: why does sulphur has 10 electrons in SO2? Very confused here and any help will be appreciated. Thanks in advance.