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Basic concept Q ,non-linear PDE , kdv

  1. Oct 6, 2014 #1
    Ut+6UUx+Uxxx=0 [kdv eq]

    Why to solve this do you need U(x,t=0)?
    Why is it a initial value problem?

    This should probably be really obvious. I think I've forgotten some basic background stuff, just starting my course in solitons...

    Thanks for your help.​
     
  2. jcsd
  3. Oct 6, 2014 #2
    Sorry I'm not sure how , if you can, edit your threads on the new layout..

    Some thoughts:
    - If we have U(x,t=0) and solve for U(x,t) , is our solution only valid for t in a small interval around t=0? Or can we solve for all t from this?
     
  4. Oct 8, 2014 #3
    bump.
     
  5. Oct 9, 2014 #4

    HallsofIvy

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    Your question doesn't make sense. You don't "have to have" a value for U(x, 0). While that, together with values for U(a, t) and U(a, b), would be sufficient since the partial differential equation is of first order in t and second order in x, it is NOT necessary.
     
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