Basic equivalent resistance problem

[qpham26]

Homework Statement

Find R_ab
https://sphotos-a.xx.fbcdn.net/hphotos-ash4/199915_496321627054024_1130826860_n.jpg

Homework Equations

R_eq = R₁R₂ / R₁+ R₂

The Attempt at a Solution

bottom 2Ω resistors in series ---> R_eq1 = 4Ω

top right 12 and 4 Ω in parallel ---> R_eq2 = 3Ω

this 3Ω and the left top 6Ω are in parallel ---> R_eq3 = 2Ω

2 resistors of 4Ω bottom left are in parallel -->R_eq4 = 2Ω

R_eq4 and R_eq3 are in series --->R_eq5 = 4Ω

R_eq5 and R_eq1 are in parallel ----> R_eq6 = 2Ω

R_ab = 3Ω + 2Ω = 5Ω

please let me know if I have gotten the correct answer.
Thanks for your time.

 

[CWatters]

I also make it 5 Ohms slightly different way..

[{(6//12//4) + (4//4)} // {2+2}] + 3

[{2 + 2} // {4}] + 3

[4//4] +3

2 + 3 = 5