1. The problem statement, all variables and given/known data Find the equivalent resistance of the circuit shown, for circuit 3.7b, the one in the upper right : https://scontent-ort2-1.xx.fbcdn.net/v/t34.0-12/14429160_641550399338143_303002326_n.png?oh=ad8d346cfcaff147c9cd7a9d2b509411&oe=57E6C47C 2. Relevant equations Rseries=Rtotal =R1+R2+.....+RN Rparallel=(Rtotal)-1=(R1)-1+(R2)-1+..... 3. The attempt at a solution So for my attempt, my assumption was that: The 18 and 12 Ω resistors were in series, so I combined them. I assumed the 20 Ω resistor at the top was in parallel with the 60Ω resistor under it and combined that. Then, the equivalent resistance of the 20 and 60 Ω resistors was in series with the 40 Ω resistor. Now, I am stuck and confused on where to continue. I was going to assume that the equivalent resistor of 55 Ω(from 60,20, and 40) was in parallel with the diagonal 50 Ω resistor and go from there, but it just seemed wrong. Please, can anyone tell me if I am on the right track or I messed up somewhere?