If I drop a ball, how far will it fall in 2 seconds? ΔX = ViT + 1/2AT^2 ΔX = (0)(2) + 1/2(9.8)(2)^2 ΔX = 19.6 m I tested this, and there is no way an object falls 19.6 m in only 2 seconds. Think about it. Drop something right now and it will only fall like 1 meter in one second. I don't understand. These equations don't fit reality to me. Can someone show me what I am doing wrong?