Basics of hydrostatic force on a plane surface

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Hydrostatic force on a plane surface is determined by the pressure exerted by a fluid, which varies based on the surface orientation. For horizontal surfaces, the pressure is uniform, making calculations straightforward as total force equals pressure times area. However, for inclined surfaces, pressure varies, complicating the thrust calculation. The discussion also includes a homework problem focused on determining hydrostatic thrust on a submerged plane surface and finding the line of action. Clarification is sought on specific calculations related to the thrust, indicating the need for better visual aids or descriptions.
Mohammad Danial
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1. Introduction

Pressure of a fluid exerts thrust on each part of a surface with which the fluid made contact. Each forces distributed over the area have a resultant magnitude and direction that is very crucial. For a horizontal surface, the pressure does not vary over the plane. Thus, the total force is the product of the pressure and the area. Its direction is perpendicular to the plane. But if the surface is not horizontal, the pressure varies at each point of the surface. Thus, the calculation of the total thrust is different.

2. Homework Statement

To determine the hydrostatic thrust acting on a plane surface immersed in water. Besides that, identify the position of the line of action of the thrust

Homework Equations


No.1.png
No.2.png


i don't get it how to get h''' especially the part sin 90( Ixx/Pcg A ). I would really appreciate it if someone can give me some guidance to understand it. Thank you

The Attempt at a Solution

 
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That's quite a complicated diagram, and far from self-explanatory. A textual description would help.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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