Beam boundary condition problem

AI Thread Summary
The discussion centers around solving a beam boundary condition problem related to vibrations. A free body diagram was created, leading to a force balance equation: $$-ku-C\frac{du}{dt}-mg+Q=\frac{d^2u}{dt^2}$$, where Q represents the upward shear force exerted by the bar on the mass. Participants seek clarification on the derivation of this equation and the role of shear force in the system, confirming that the masses are attached to the end of the bar. The shear force is essential to ensure that the mass moves in conjunction with the bar. Understanding these concepts is crucial for progressing in the vibration analysis of the beam.
Motorbiker
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Homework Statement
derive the boundary conditions of a beam whichcarries masses and is supported by springs and dampers
Relevant Equations
equations are shown in my working
vibration question.png



In my working, I have drawn a free body diagram of the LHS of the beam, I obtained some equations but after that not sure what I need to do. Usuaully in vibration problems you are given BC's then you plug them into the general solution to obtain the frequency equation.

Please can you help me understand how to do this problem? I'm really struggling to understand how to do it.

vibration question.png


working.jpeg
 
Last edited by a moderator:
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Please use LaTex to render equations. A guide is in the lower left hand corner of your response window.
 
Chestermiller said:
Please use LaTex to render equations. A guide is in the lower left hand corner of your response window.
I think I showed the equations in my working?
 
Motorbiker said:
I think I showed the equations in my working?
It's unreadable.
 
Chestermiller said:
It's unreadable.
I’ve attached another picture of my working, please let me know if you can read this one.

F3C4EF10-986E-4B71-A02C-B6325D4B5520.jpeg
 
Last edited by a moderator:
It should be $$-ku-C\frac{du}{dt}-mg+Q=\frac{d^2u}{dt^2}$$where Q is the upward shear force exerted by the bar on the mass.
 
Last edited:
Chestermiller said:
It should be $$-ku-C\frac{du}{dt}-mg+Q=\frac{d^2u}{dt^2}$$where Q is the upward shear force exerted by the bar on the mass.
Thanks for this. Could you please explain how you got this equation? I want to understand this better.
 
Motorbiker said:
Thanks for this. Could you please explain how you got this equation? I want to understand this better.
it is from the free body diagram on the mass. It is the force balance equation on the mass.
 
Chestermiller said:
it is from the free body diagram on the mass. It is the force balance equation on the mass.

I'm guessing this equation applies to both sides?
Also how do we know that there is shear force acting on the beam?
 
  • #10
Please can I get someone help with this? I don't really understand the solution fully, where does the shear force come from?
 
  • #11
Motorbiker said:
Please can I get someone help with this? I don't really understand the solution fully, where does the shear force come from?
Are the masses attached to the end of the bar or not?
 
  • #12
Chestermiller said:
Are the masses attached to the end of the bar or not?

Yes they are.
 
  • #13
Motorbiker said:
Yes they are.
The shear force makes sure that the mass moves with the bar.
 

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