B Predicting Supernovas: Math Question and Mental Exercises | Expert Help Needed

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The discussion revolves around the challenges of predicting astronomical events, specifically supernovas, and the mathematical calculations involved. The original poster seeks assistance with statistics to better understand the odds of their predictions, which include specific dates for potential nova and supernova appearances. They express confusion over how to quantify the probability of these events, particularly in relation to their 67-day advance notice. A response clarifies that the odds of prediction do not work as simply as the poster suggests, emphasizing that a prediction made in advance does not equate to a straightforward probability calculation. The conversation highlights the complexities of statistical reasoning in the context of astronomical predictions.
K. Doc Holiday
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I suck at math. Help?

Any good at statistics? I could use your help. I like to make nearly impossible predictions but I suck at calculating odds of success.

On November 2nd, 2016 at 15:54 Mountain Standard Time I made an astronomy prediction on my Facebook page:

P.M.* January 9, 2017:
IK Pegasi B appears as a NOVA.

A.M.* January 16, 2017:
AN Ursae Majoris B appears as a type 1a SUPERNOVA. (Don't fly anywhere)

*Mountain Standard Time

I am not trying to upset anyone. I do mental exercises to expand my view of reality.

I made the prediction 67 days in advance = 1 in 67. Half day "P.M." should cut it in half = 1 in 134?
Or?

Current consensus is IK Pegasi B won't nova for 2 million years. So, is 1 in 2 million closer?

To the half day is 365 times 2 = 730 times 2 million = 1 in 1,460,000,000?

Since no one considers polar white dwarfs a possibility for a supernova event I assume it is fair to calculate the odds of that happening at zero?

Once again I apologize for asking silly questions and i appreciate your patience.

Sincerely
Doc

ps. Merry Christmas [emoji320][emoji318][emoji268][emoji6]
 
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K. Doc Holiday said:
I
I made the prediction 67 days in advance = 1 in 67.

Sorry, it doesn't work that way at all. 1 in 67 means a certain degree of surprise/uncertainty. Specifying how many days in advance doesn't quantify that way. I can predict that in 67 years it will rain somewhere in the world. I did it 67 days in advance, but the odds aren't 1 in 67.

For sure though, specifying something more in advance than specifying it right before it happens is more impressive, and might deserve more impressive odds, but it won't be 1 in 67.
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

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