- #1
firavia
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Refering to the image uploaded can we say by applying bernouli equation and darcy equation the following :
Pa/(guamma) + Va^2/2.g + Za - (head loss in pipe ab using darcy equation )-(head lossin pipe bc using darcy equation) = Pc/(guamma) + Vc^2/2.g + zc . ??
and the same thing between point a and point d ?
if we can do so , thn the head loss in pipe ab must be diferent thn the head loss in pipe bd with a value that is equal to the difference between the dinamic velocities energy in c and d ? am I right ?
why we used to say that head loss are both equal in pipe bc and bd ?
P.S : pc and pd are at 0 atmospheric pressure .
Pa/(guamma) + Va^2/2.g + Za - (head loss in pipe ab using darcy equation )-(head lossin pipe bc using darcy equation) = Pc/(guamma) + Vc^2/2.g + zc . ??
and the same thing between point a and point d ?
if we can do so , thn the head loss in pipe ab must be diferent thn the head loss in pipe bd with a value that is equal to the difference between the dinamic velocities energy in c and d ? am I right ?
why we used to say that head loss are both equal in pipe bc and bd ?
P.S : pc and pd are at 0 atmospheric pressure .