Binary search: the math behind 32 steps

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Binary search efficiently locates an entry in a sorted dataset by repeatedly dividing the search space in half. For a dataset with 4 billion entries, a maximum of 32 steps is required, as determined by the logarithm base 2 of the number of entries. Increasing the dataset to 8 billion requires one additional step, totaling 33. The discussion emphasizes understanding the logarithmic relationship and encourages experimentation with smaller datasets to grasp the concept. Additionally, a side exercise illustrates that for 512 contestants, it takes 9 rounds to determine a winner, reinforcing the power of logarithmic calculations in various scenarios.
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Homework Statement



Hello!
I have just heard in one online lecture that if for example there is a phone book with 4 billion entries (or a data set
with 4 billion entries), then to find one entry (for example, Kim Simth) I need maximum 32 steps.
If the amount of entries is increased by half, ie to 8 biliion, then it's ll take 33 steps.

I understand the algorithm of how to do binary search (divide by half, by half, etc). But I have no clue on how to
compute the math behind those 32 steps, and how log(n) works in this case.

Please, help me with your advice on how to learn this, what are good resources on this matter, where to read about
it (not in Wikipedia, sorry).

Thank you very much!
 
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Powers of 2 are very powerful ! Play around with 8, 16 entries to see how itt works. Note that the array has to be sorted in order to do this.

Side exercise: if there are 512 contestants at Wimbledon, how many matches have to be played until Djoko gets the first prize ? And how many rounds does that take ? Same thing !
 
BvU said:
Powers of 2 are very powerful ! Play around with 8, 16 entries to see how itt works. Note that the array has to be sorted in order to do this.

Side exercise: if there are 512 contestants at Wimbledon, how many matches have to be played until Djoko gets the first prize ? And how many rounds does that take ? Same thing !
I am not sure I correctly understood the nice Wimbledton side task :) Is it 9 steps in worst case scenario? 512 = 2^9, i.e. log 2( 512) = 9
 
Nine rounds is right. How would you calculate the total number of matches that it takes ? (this doesn't help with your original post, but it's a nice thingy to carry with you for later on).

Back to the BS (:smile:): If it takes nine steps for 29 entries, how many steps for 232 ? How much is 232 ? The math is really simple, actually! And the number of steps is the 2 logarithm of the number of entries. Piece of cake!
 
BvU said:
And the number of steps is the 2 logarithm of the number of entries.
In other words, the number of steps = ##\log_2(\text{entries})##

Here ##\log_2(4) = 2, \log_2(8) = 3##, and so on.
 

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