What is the Binding Energy per Nucleon of 238U in MeV?

[felipenavarro]

Homework Statement

Find the binding energy per nucleon of
238
92 U in MeV

Homework Equations

ΔM= ideal mass - atomic mass
Ebind= ΔM * 931.5

The Attempt at a Solution

first i found the diference in mass from ideal weight and atomich weight which is 1.98499. then i multiplied it by 931.5 which gives me a total binding energy of 1849.0181 MeV.
Now, i understand that a nulceon is a pair made of a proton and a neutron so i should divide my answer by the number of nucleons in the atom. but there are more neutrons than protons in U so i don't know what should i divide by!

 

[ehild]

"In chemistry and physics, a nucleon is one of the particles that makes up the atomic nucleus. Each atomic nucleus consists of one or more nucleons, and each atom in turn consists of a cluster of nucleons surrounded by one or more electrons. There are two kinds of nucleon: the neutron and the proton. The mass number of a given atomic isotope is identical to its number of nucleons. Thus the term nucleon number may be used in place of the more common terms mass number or atomic mass number." http://en.wikipedia.org/wiki/Nucleon

ehild

 

[felipenavarro]

oh, it makes sense now, thanks!

 

[CAF123]

Total binding energy, $E_b = (Zm_p + Nm_n - M(Z,N))c^2$
You should find that, in adding up all the constituent nucleons that their sum is greater than that of the mass of the actual nucleus. This 'extra' mass is the binding energy.

The binding energy per nucleon $= \frac{E_b}{A},$ where A is the number of nucleons (number of protons and neutrons)

EDIT: I see that your question has already been answered

 

[felipenavarro]

yea haha, thanks anyway