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## Homework Statement

So 5 numbers are drawn from pile of 10 balls. After the draw, the ball is put back in the pile. So you always have 10 choices for the ball.After drawing 5 balls, another one is drawn for the sixth number.

What is the chance of getting the winning number-combination 848235.

## Homework Equations

## The Attempt at a Solution

So I have 10

^{5}possible solutions for the first part. Now I need to find the chance, to get a number that is a subset of (2,3,4,5,8,8).

I have these six numbers. I need to know how many 5-number combinations, can be made out of these 6 numbers.

I used the permutation formula and I got 360. I don't think that is right.

How can I know, how many 5-digit numbers can I make from these 6 numbers, given that one is repeating.

Example:

23458

23588

etc.

After I know how many combinations I have for those 5 digit numbers, I can make the probability of getting a combination of those 5 numbers in the first part.

For the second draw, I am still thinking. Maybe because, we again have 10 balls, and 5 different numbers to be drawn, chance is 1/2. So I would multiply the final result(probability for 5 digits) with 1/2.