(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The College Board reports that 2% of the 2 million high school students who take the SAT each year receive special accommodations because of documented disabilities. Consider a random sample of 25 students who have recently taken the test.

a.) What is the probability that exactly 1 received a special accommodation?

b.) What is the probability that at least 1 received a special accommodation?

2. Relevant equations

[tex]\begin{pmatrix}

n\\

x\\

\end{pmatrix}p^x(1-p)^{(n-x)}[/tex]

3. The attempt at a solution

a.)[tex]\begin{pmatrix}

25\\

1\\

\end{pmatrix}.02^x(1-.02)^{(25-1)} = .3079[/tex]

30% seems kind of high. If 40,000 students out of 2,000,000 were {success} and chose 25 of the 2,000,000, there's a 30% chance I'd get 1 of the 40,000? That, just seems too high for some reason.

b.)[tex]

\sum_{x=1}^{25}

\begin{pmatrix}

25\\

x\\

\end{pmatrix}.02^x(.98)^{(25-x)}[/tex]

Does this look right? How can I calculate this? I don't believe I have to simplify it, per instructor's orders...but I'm not sure if I have it right to begin with.

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# Homework Help: Binomial Probability Distribution

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