- #1

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How these calculations are done,i am not getting ,if i will learn this it will make my life way easier. please help.How we can understand that where should we put ( ^)[to the power raised to].......?

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- Thread starter gracy
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- #1

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How these calculations are done,i am not getting ,if i will learn this it will make my life way easier. please help.How we can understand that where should we put ( ^)[to the power raised to].......?

- #2

jedishrfu

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So what is it you're trying to figure out? Humans have largely the same DNA packaged into the same chromosomes. There is still a large variety of differences but not necessarily from codon to codon. We gain our traits mostly in how the chromosomes are paired from our mother's chromosomes and our fathers chromosomes. You might want to think more at the gene level than at the codon level.

http://en.m.wikipedia.org/wiki/Chromosomes

There's a table inside that shows the number of genes in each chromosome.

- #3

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- 83

I have given jut two examples,actually i want to understand how such( 4^3/ 2^23)calculation is done?

So what is it you're trying to figure out? Humans have largely the same DNA packaged into the same chromosomes. There is still a large variety of differences but not necessarily from codon to codon. We gain our traits mostly in how the chromosomes are paired from our mother's chromosomes and our fathers chromosomes. You might want to think more at the gene level than at the codon level.

http://en.m.wikipedia.org/wiki/Chromosomes

There's a table inside that shows the number of genes in each chromosome.

- #4

Pythagorean

Gold Member

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4^3 means multiply 4 three times. So it would be:

4^3 = 4*4*4 = 16*4 = 64

4^3 = 4*4*4 = 16*4 = 64

- #5

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I know 4^3 = 4*4*4 = 16*4 = 64 .I just want to know how can i understand that here i have to calculate in this way.As in my examples ,there are four nitrogenous bases and i want to figure out how many different combinations i can make if i make pair of three of them i.e codon.If i will sit to write each and every combination it will be very tedious and tough task but in my textbook it is just calculated in this way 4^3 = 4*4*4 = 16*4 = 64 .64 different combinations.That's what i want to learn how to do such calculations.Four different bases .i want to make pair of three so how it comes out to do 4^3 why not 4 multiplied by 3?That's what i want to learn.4^3 means multiply 4 three times. So it would be:

4^3 = 4*4*4 = 16*4 = 64

- #6

Pythagorean

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Think of it this way. If you have a switch with an on off state, that's one switch with two states, so: 2^1

If you have two switches with two states each, there are four total states the whole two system switch can be in: 2^2=4

If a widget has 4 states and you have three widgets, the total number of states is 4^3.

You can also count them out. For two switches each with two states, all your states are:

00

01

10

11

Four states, 2^2!

If you have two switches with two states each, there are four total states the whole two system switch can be in: 2^2=4

If a widget has 4 states and you have three widgets, the total number of states is 4^3.

You can also count them out. For two switches each with two states, all your states are:

00

01

10

11

Four states, 2^2!

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- #7

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I didn't understand this.Is it in this waythat's one switcj wotu two states,

one switch with two states.

- #8

Pythagorean

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I fixed that typo :) sorry, mobile keyboard.

- #9

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- #10

Pythagorean

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- #11

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AA.............Four things with three states .There were four nitrogenous bases.Because 4^3 was three things with four states

- #12

- 2,486

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Now i am getting confused.According to your examples States^(number of things),But according to mine number of things^their variable states.What next?

- #13

Pythagorean

Gold Member

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000

001

010

011

100

101

110

111

That's 8. Wheres 3^2 would be 9. So which formula is right?

- #14

Pythagorean

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Also, a codon is three base pairs and the pairs have four possible things they could be: A C G or T, so 4^3 is right!

Edit: actually I think that T should be a U.

edit 2: genes -> base pairs

Edit: actually I think that T should be a U.

edit 2: genes -> base pairs

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- #15

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But i am taking it in this way there are 4 nitrogenous bases,and they are arranged in codon such that they can be given either of three positions in codon.So things^their variable states.I am taking number of things as number of bases you are taking number of things as number of genes in a codon.So ...........Also, a codon is three genes and the genes have four possible things they could be: A C G or T, so 4^3 is right!

- #16

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- #17

Pythagorean

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- #18

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So four base pair so four things. How three things^variable states?

- #19

Pythagorean

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- #20

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Now i understood.Thanks a lot.

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