Biology Differential Equations/Dimensional Analysis

Click For Summary
SUMMARY

The discussion focuses on solving differential equations related to a chemostat model in biology, specifically addressing parts a, b, and c of a past exam paper. The chemostat maintains a constant volume while nutrients are supplied and bacteria multiply. The participants analyze the coupled differential equations governing bacterial and nutrient concentrations, emphasizing that bacterial death is negligible. Dimensional analysis is performed to determine the dimensions of constants, identifying one as dimensionless, and substitution techniques are used to simplify the equations for comparison.

PREREQUISITES
  • Understanding of chemostat dynamics and bacterial growth models
  • Familiarity with differential equations and their applications in biological systems
  • Knowledge of dimensional analysis and its significance in mathematical modeling
  • Proficiency in calculus, particularly the Chain Rule for variable substitution
NEXT STEPS
  • Study the mathematical modeling of biological systems using differential equations
  • Learn about the application of dimensional analysis in various scientific fields
  • Explore the use of the Chain Rule in solving complex differential equations
  • Investigate the behavior of chemostats under varying conditions and parameters
USEFUL FOR

Students preparing for exams in biological mathematics, researchers modeling microbial growth, and educators teaching differential equations in biological contexts.

ceejay2000
Messages
6
Reaction score
0
http://img209.imageshack.us/img209/7596/mbiolq1.jpg


Hi PF, any help with parts a, b and c would be most appreciated. I haven't had a go at these simply because I don't know where to start. There are parts d) etc. onwards that I have done already; it seems to be the simple stuff I struggle with!
The question comes from a past paper for an exam I am revising for and the exam is on Wednesday so I'm desperate! Ha ha, thanks in advance!
 
Last edited by a moderator:
Physics news on Phys.org
a) A chemostat is a tank with liquid culture medium kept at a fixed volume. The chemostat receives a constant influx of nutrients at a fixed flow rate, and medium is siphoned off at the same flow rate (in order to maintain constant volume). A fixed inoculum of bacteria is introduced at the start of the process, and only natural multiplication increases their numbers.

Given this info, can you decipher the coupled differential equations? Think of what processes cause the bacterial concentration to respectively increase and decrease. You may assume that death of bacteria is not a factor here (as the tank is kept adequately supplied by nutrients at all times). Now think of what processes cause the nutrient concentration to respectively increase and decrease.

b) The dimensional analysis is easy. The LHS of both equations has the dimensions of concentration/time. Every individual term on the RHS (separated by addition or subtraction) has the same dimension. Multiplying and dividing dimensions works just like in algebra. Can you now work out the dimensions of those constants? Which one (only one) is dimensionless?

c) This is a bit more tricky. Start by substituting [itex]x = kb, y = pn[/itex] and [itex]\tau = qt[/itex] where [itex]k, p[/itex] and [itex]q[/itex] are constants into the reduced set of differential equations (in [itex]x[/itex] and [itex]y[/itex]). Work through the calculus (you'll need to use Chain Rule to handle the time parameter [itex]\tau[/itex]) and get the equations into a form comparable with the original set (in [itex]b[/itex] and [itex]n[/itex]). Then compare coefficients to deduce the values of [itex]k, p[/itex] and [itex]q[/itex].

You should find [itex]\mathbb{D} = \frac{\phi{r}}{\gamma^2}[/itex]. Use this to check your final answer.
 
That was really helpful; thanks for your time!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
13
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K