Blackhole Physics: Can Particles Escape Event Horizon?

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In summary: I don't understand, does the tunneling have to happen outside the event horizon? I thought that was what you were saying.I don't understand, does the tunneling have to happen outside the event horizon? I thought that was what you were saying.
  • #1
Flatland
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When a particle fall past the event horizon, is it possible to escape via quantum tunnelling?
 
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  • #2
Just my guess:

Since the particle is acclerating towards the center of the black hole, any quantum-tunneling potential would be expressed in that direction also.
 
  • #3
well, from what I understand, quantum tunneling doesn't really have a "direction"
 
  • #4
Flatland said:
well, from what I understand, quantum tunneling doesn't really have a "direction"

Er... yes it does. Look at the wavefunction. It has "k", the wave vector, which is built in into the tunneling matrix element. And directional tunneling is something that is used to study the density of states of material along a particular crystallographic direction.

Zz.
 
  • #5
I don't understand, how can it have a direction? It's not like when tunneling happens, a particle travels into any particular direction, it's just there. It doesn't traverse any space.
 
  • #6
Flatland said:
I don't understand, how can it have a direction? It's not like when tunneling happens, a particle travels into any particular direction, it's just there. It doesn't traverse any space.

It has a direction depending on the orientation of the tunneling barrier and the direction of the particle's momentum, i.e. the "k" in the wavefunction. The largest probability of tunneling given a constant momentum magnitude is for the particle to be perpendicular to the barrier. So yes, there is a preferred direction.

Zz.
 
  • #7
Ok I kinda understand what you mean in that after a particle tunnels there is a particular direction in relation to where it was previously. But how does that prevent it from escaping a black hole when direction is irrelevant?
 
  • #8
Flatland said:
Ok I kinda understand what you mean in that after a particle tunnels there is a particular direction in relation to where it was previously. But how does that prevent it from escaping a black hole when direction is irrelevant?

I wouldn't know. I've never done tunneling through a black hole barrier, and from what I can gather, neither have anyone else. Not only that, has anyone has actually established a theoretical description of such a thing? If not, aren't we just playing Let's Guess?

Zz.
 
  • #9
Well, granted that no one has made any direct observance, but I'm speaking about in theory. Does the laws of physics prevent this from happening?
 
  • #10
Flatland said:
Well, granted that no one has made any direct observance, but I'm speaking about in theory. Does the laws of physics prevent this from happening?

You have established the formulation FIRST. There is a difference between our current understanding of tunneling, and what you are asking. Our conventional tunneling requires the existence of well defined space (and time) on both sides of the tunneling barrier, AND inside the tunneling barrier.

Do you have such a thing for your black hole? How does one defined the "state" of a particle inside a black hole? Is this a well-defined and well-developed physics?

Zz.
 
  • #11
I'm pretty sure I'm worng...but could hawking radiation be defined as a sort of tunneling?
 
  • #12
simon009988 said:
I'm pretty sure I'm worng...but could hawking radiation be defined as a sort of tunneling?

No. It is the creation of particle-antiparticle pair near the event horizon where one gets swallowed, and the other doesn't.

Zz.
 
  • #13
does one of the particle-antiparticle pair have to tunnel out of the space near the event horizon in order to get out and get recorded as hawking raditation? because won't parts of the wavefunctionof the pair that will escape be kind of in the event horizon.
 
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  • #14
simon009988 said:
does one of the particle-antiparticle pair have to tunnel out of the space near the event horizon in order to get out and get recorded as hawking raditation? because won't parts of the wavefunctionof the pair that will escape be kind of in the event horizon.

Er.. no. This occurs near and outside the event horizon. Why would it need to tunneling to be outside? It is already outside. But since the momentum of each particle will be opposite each other, it stands to reason that one of the pair will be moving towards the event horizon and gets swallowed, while the other can escape since it is already outside. Where is the tunneling barrier here?

Zz.
 

1. What is the event horizon of a black hole?

The event horizon of a black hole is the point of no return, beyond which the gravitational pull is so strong that nothing, including light, can escape. It is the boundary where the escape velocity exceeds the speed of light.

2. Can particles escape the event horizon of a black hole?

No, particles cannot escape the event horizon of a black hole. The gravitational pull at this point is too strong for anything to escape, including particles and even light.

3. What is the relationship between escape velocity and the event horizon of a black hole?

The event horizon is where the escape velocity equals the speed of light. This means that any object or particle that crosses the event horizon will be unable to escape due to the strong gravitational pull.

4. Are there any exceptions to the rule that particles cannot escape the event horizon of a black hole?

There is a theoretical concept known as Hawking radiation, which suggests that black holes can emit particles due to quantum effects near the event horizon. However, this process is extremely slow and does not significantly impact the size or mass of the black hole.

5. How does the size of a black hole's event horizon relate to its mass?

The size of a black hole's event horizon is directly proportional to its mass. The more massive a black hole is, the larger its event horizon will be. This is because the stronger the gravitational pull, the larger the radius at which the escape velocity will equal the speed of light.

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